(not <em>a</em> or not <em>b</em>) implies <em>c</em> <==> not (not <em>a</em> or not <em>b</em>) or <em>c</em>
so negating gives
not [(not <em>a</em> or not <em>b</em>) implies <em>c</em>] <==> not[ not (not <em>a</em> or not <em>b</em>) or <em>c</em>]
which we can simplify somewhat to
not (not (not <em>a</em> or not <em>b</em>)) and not <em>c</em>
(not <em>a</em> or not <em>b</em>) and not <em>c</em>
(not <em>a</em> and not <em>c</em>) or (not <em>b</em> and not <em>c</em>)
not (<em>a</em> or <em>c</em>) or not (<em>b</em> or <em>c</em>)
not ((<em>a</em> or <em>c</em>) and (<em>b</em> or <em>c</em>))
not ((<em>a</em> and <em>b</em>) or <em>c</em>)
2z2-9z+5
you have to do 23 -18 to get the 5 and since there is nothing else that u can factor at the moment u just need to right in the proper order which is 2z2-9z+5
Answer:
0.0816
Step-by-step explanation:
Given:
- Total number of students = 5000
- Number of students taking an online class = 1200
- Number of students prefer watching baseball to football = 1700
Let O = Students taking an online class
Let B = Students prefer watching baseball to football
Therefore,
P(O) = 1200/5000 = 0.24
P(B) = 1700/5000 = 0.34
If events O and B are independent,
⇒ P(O ∩ B) = P(O) · P(B)
= 0.24 × 0.34
= 0.0816
Answer:
D
Step-by-step explanation:
