Answer:
the first one is 5. 5 and second is 5
Step-by-step explanation:
sorry i couldnt do the others
Answer:
Slope intercept form is y=mx+b
Let’s first find the slope, which is y2-y1/x2-x1
Let’s make the point (-2,-5) our x1 and y1 and let’s make the point (3,5) our x2 and y2.
5+5/3+2
10/5
2 = slope
So far, our equation is looking like this:
y=2x + b
To find the y-intercept (b), let’s plug in one of the points.
Let’s use the point (3,5)
(5)=2(3) + b
5=6 + b
What adds to 6 to equal 5? -1
So, our y-intercept is going to be -1
Finally, our equation is going to look like this:
y=2x-1
Hope I helped!
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Answer:
23 ^ ( a+b)
Step-by-step explanation:
23^a *23^b
Since the bases are the same, we can add the exponents
23 ^ ( a+b)
