Answer: 84.13%
Step-by-step explanation:
Given : The scores in a a language test with normally distributed.
Mean : 
Standard deviation: 
Let x be the random variable that represents the scores of students.
Formula for z-score: 
For x= 60 , we have

The probability f test takers scored a 60 or above :-

Hence, the percentage of test takers scored a 60 or above = 84.13%
Answer:
24
Step-by-step explanation:
3.2x5 x1.5=24
Hope this helps :)
Answer:
16/28
Step-by-step explanation:
Multiply both the denomator and numerator by 4
Answer:
32 ? im not 100% sure tho
Step-by-step explanation: