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Aleksandr-060686 [28]
2 years ago
8

If f(x) = 4* + 12x and g(x) = 5x - 1, find (f + g)(x).​

Mathematics
1 answer:
Rudik [331]2 years ago
4 0

Answer:

\large\boxed{(f+g)(x)=4^x+17x-1}

Step-by-step explanation:

(f+g)(x)=f(x)+g(x)\\\\f(x)=4^x+12x,\ g(x)=5x-1\\\\(f+g)(x)=(4^x+12x)+(5x-1)=4^x+17x-1

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The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)
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Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}

Now, we have to find the quotient of the above expression.

So, here we go:

Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)

Now, we will divide the above simplest form with g(x):

\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2

Hence, the quotient is (x-2).


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3 years ago
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Step-by-step explanation:

7 0
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Suppose the circumference of a circle is 4, pi. What is its diameter?
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I hope this helps!
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For this case we have the following variables:
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