If f(x) = 4* + 12x and g(x) = 5x - 1, find (f + g)(x).

Mathematics

1 answer:

Rudik [331]3 years ago

4 0

Answer:

$\large\boxed{(f+g)(x)=4^x+17x-1}$

Step-by-step explanation:

$(f+g)(x)=f(x)+g(x)\\\\f(x)=4^x+12x,\ g(x)=5x-1\\\\(f+g)(x)=(4^x+12x)+(5x-1)=4^x+17x-1$

You might be interested in

Helppp 8th grade algebra <br> C. Six units left<br> D.six units right

yanalaym [24]

D, six units to the right. This is the answer because the pre-image is six to the left of the newest image. Just count the spaces away!

5 0

3 years ago

I need help I can’t figure it out

dusya [7]

Answer:

$\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}$

Step-by-step explanation:

$\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}$

7 0

3 years ago

A line is perpendicular to y = 1/4x- 8

postnew [5]

Answer:

perp-9xc

Step-by-step explanation:

2. tiy have t

7 0

3 years ago

Look at pic 10 pts will mark brainilest

seropon [69]

Answer:

c may be the correct one l am 55% sure

6 0

2 years ago

Read 2 more answers

a 14 ounce energy drink contains 10 1/2 teaspoons of sugar. How much sugar is in one ounce of the drink?

Y_Kistochka [10]

In this case u need to divide 10 1/2 by 14 coz theres 14 ones in 14
so 10 1/2 divided by 14 = 0.75
<em>so theres 0.75 sugar in one ounce of drink ;)</em>

5 0

3 years ago

If f(x) = 4* + 12x and g(x) = 5x - 1, find (f + g)(x).​

If f(x) = 4* + 12x and g(x) = 5x - 1, find (f + g)(x).