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Yakvenalex [24]
4 years ago
7

Can you construct a triangle that has side lengths 8 m 10 m and 19 m

Mathematics
1 answer:
Alexxandr [17]4 years ago
4 0

Answer:

NO

Step-by-step explanation:

Draw a triangle and label the sides a, b and c. Now we must know the rule you can use for drawing any triangle:

A+B> c

A+C>B

B+C>A

Sub you numbers into the rule:

8+10, is it greater that 19?

No, 8+10=18 and 18<19

This is proof that you can not draw a triangle with the side lengths of 8m, 10m and 19m.

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12x -20=n (3x-5)<br><br> I need help I don’t get it please help me.
Salsk061 [2.6K]

Answer:

The value of n = 4 and  

The value of x = \frac{5}{3}

Step-by-step explanation:

Method I:

As given, 12x -20=n (3x-5)      .........(1)

Firstly , take 12x - 20

As 12x - 20 can be written as 4(3x - 5)

∴ equation (1) becomes

4(3x - 5) = n (3x-5)

Divide the equation by (3x-5) , we get

4 = n

Method II:

As given, 12x -20=n (3x-5)

⇒12x - 20 = 3nx - 5n

⇒12x - 3nx = 20 - 5n

⇒3x(4 - n) = 5( 4 - n)

Divide the equation by (4-n) , we get

3x = 5

⇒ x = \frac{5}{3}

∴ we get

n = 4 and  x = \frac{5}{3}

Now, check that value of n and x satisfies the equation or not

12(\frac{5}{3}) - 20 = 4( 3(\frac{5}{3}) - 5)

⇒4(5) - 20 = 4(5 - 5)

⇒20 - 20 = 4(0)

⇒ 0 = 0

Hence , we get

The values of x and n satisfies the equation

so, we get

n = 4 and  x = \frac{5}{3}

5 0
3 years ago
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