Answer: d) 4
<u>Step-by-step explanation:</u>
The x-intercept is when y = 0
![y=\dfrac{x-4}{x^2-4}\\\\\\\text{Set y equal to zero:}\\0=\dfrac{x-4}{x^2-4}\\\\\\\text{Cross multiply:}\\0=x-4\\\\\\\text{Solve for x:}\\4=x](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7Bx-4%7D%7Bx%5E2-4%7D%5C%5C%5C%5C%5C%5C%5Ctext%7BSet%20y%20equal%20to%20zero%3A%7D%5C%5C0%3D%5Cdfrac%7Bx-4%7D%7Bx%5E2-4%7D%5C%5C%5C%5C%5C%5C%5Ctext%7BCross%20multiply%3A%7D%5C%5C0%3Dx-4%5C%5C%5C%5C%5C%5C%5Ctext%7BSolve%20for%20x%3A%7D%5C%5C4%3Dx)
18 - 4 - 2/7j - 6/7j + 5 =
18 - 4 + 5 - 2/7j - 6/7j=
19 - 8/7j
Answer:
Please check the explanation.
Step-by-step explanation:
- We know that the domain of a function is the set of input or argument values for which the function is real and defined.
Thus, the domain of the first relation is: {-2, -1, 0, 2}
- We also know that the range of a function is the set of values of the dependent variable for which a function is defined.
Thus, the range of the first relation is: {-4, -2, 2}
Given the second relation
x y
-4 -2
-2 1
1 4
4 4
- We know that the domain of a function is the set of input or argument values for which the function is real and defined.
Thus,
The domain of the second relation is: {-4, -2, 1, 4}
- We also know that the range of a function is the set of values of the dependent variable for which a function is defined.
Thus,
The range of the second relation is: {-2, 1, 4, 4}
The answer to this question is 125%. Please mark brainlest!
22
bc I know that is 22 so just put that