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Natasha2012 [34]
3 years ago
10

When four digits (between 0 and 9 inclusive) are randomly selected with replacement for a lottery ticket, what is the probabilit

y that at least one digit will be a zero?
Mathematics
1 answer:
Assoli18 [71]3 years ago
4 0
We are asked to determine the probability of having at least one digit of zero in a winning lottery number that is composed of four digits from the set of numbers from 0 to 9. To determine the probability to be known, we can approach this problem by computing for the probability by counting theory for each digit.

Digit 1: there are 10 choices, so the probability is 1/10
Digit 2: there are only9 choices, probability of 1/9
Digit 3: there are also 9 choices, probability of 1/9
Digit 4:  9 digits as 0 is not a included

*(numbers beginning with zero do not count zero as part of the number)

Hence the probability is (1/10)*(1/9)*(1/9)*(1/9) = <span>0.000137</span>
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Sliva [168]

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7/11 (Simplified Already)

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Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

25×3522=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

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This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 70 and 110 using

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70÷10110÷10=711

Therefore:

25÷2235=711

Solution by Formulas

Apply the fractions formula for division, to

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2×355×22

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Therefore:

2/5÷22/35=7/11

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