Question

H+j + 2k = 164h + 4j + 2k = 52h + 2j + k = 31​

Answer 1

Answer and explanation:

h

Subtract h + j + 2k = 16 by 4h + 4j + 2k = 5

    h + j + 2k = 16

-(4h + 4j + 2k = 5)

  -3h - 3j = 11    Then add 3j to both sides to get -3h alone

  -3h = 11 + 3j   Now divide both sides by -3 to get h

     h = $\frac{11 + 3j}{-3}$ = $-\frac{11}{3} - j$

j

Plug in h and k to h + j + 2k = 16 ---> $-\frac{11}{3} - j$ + j + 2(1) = 16

Then add any like terms together $-\frac{11}{3} + \frac{6}{3}$ + 2j = 16

Add $-\frac{5}{3}$ on both sides 2j = $\frac{5}{3}$ + 16

Divide both sides by 2 $\frac{2j}{2} = \frac{\frac{5}{3}}{2}$

You can divide a fraction by a fraction, so you do kcf  j = $\frac{5}{3}$ · $\frac{2}{1}$ = $\frac{10}{3}$

k

Multiply h + j + 2k = 16 by 2 --->  2h + 2j + 4k = 32

Then subtract 2h + 2j + 4k = 32 by 2h + 2j + k = 31

  2h + 2j + 4k = 32

 -(2h + 2j + k = 31)

                  3k = 1  Divide both sides by 3 to get k

                    k = 1