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JulsSmile [24]
4 years ago
3

Match its group with its percentage or mean using the table below.

Mathematics
1 answer:
natita [175]4 years ago
3 0

Answer:

1) \bar x = 6.2, 2) \bar x = 8.75, 3) \bar x = 4.5, 4) p = 40\,\%, 5) p = 60\,\%, 6) p = 10\,\%

Step-by-step explanation:

1) Mean length of all fish in the sample:

\bar x = \frac{12+5+3+5+8+2+10+9+4+4}{10}

\bar x = 6.2

2) Mean length of adult fish in the sample:

\bar x = \frac{12+5+8+10}{4}

\bar x = 8.75

3) Mean length of juvenile fish in the sample:

\bar x = \frac{5+3+2+9+4+4}{6}

\bar x = 4.5

4) Percentage of sample that were adult fish:

p = \frac{4}{10}\times 100\,\%

p = 40\,\%

5) Percentage of sample that were juvenile fish:

p = 100\,\% - 40\,\%

p = 60\,\%

6) Percentage of sample that were juveniles over 8 inches long:

p = \frac{1}{10}\times 100\,\%

p = 10\,\%

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Answer:

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And we can find this probability with this difference and using the normal standard table:

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Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

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And the best way to solve this problem is using the normal standard distribution and the z score given by:

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If we apply this formula to our probability we got this:

P(141.8

And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

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