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Bogdan [553]
3 years ago
10

The areas of two similar triangles are 75m2 and 300m2. The length of one of the sides of the second triangles is 9m. What is the

length of the corresponding side in the first triangle?
Mathematics
1 answer:
Ymorist [56]3 years ago
4 0

Answer:

4.5 m

Step-by-step explanation:

The area of two similar triangles are 75 m2 and 300 m2. This gives you the scale factor of the triangles:

\dfrac{A_{small}}{A_{large}}=k^2\Rightarrow k^2 =\dfrac{75}{300}=\dfrac{3}{12}=\dfrac{1}{4}\Rightarrow k=\dfrac{1}{2}.

Then you can find the length of the corresponding side:

\dfrac{side_{small}}{side_{large}}=k\Rightarrow =\dfrac{side_{small}}{9}=\dfrac{1}{2},\ side_{small}=\dfrac{9}{2}=4.5\ m.

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Find the surface area of the composite figure.
ELEN [110]

Answer:

644cm^2

Step-by-step explanation:

First we'll work out the surface area of the pink figure.

That's the area of the two 5 by 6 rectangles on the top and bottom, plus the area of the two 5 by 20 and two 6 by 20 rectangles on the sides.

However, we note that the purple figure is blocking out a 6 by 12 section on the pink figure, so we'll need to subtract this.

The above works out to 2\times(30+100+120)-72=428 cm^2.

Then we'll work out the surface area of the purple figure.

This will be the area of the two 4 by 6 rectangles at the top and bottom, plus the area of the two 4 by 12 and one 6 by 12 rectangles on the sides. Note that there's only one 6 by 12 rectangle because the other face is joined to the pink figure, so it's blocked out.

That's 2\times(24+48)+72=216cm^2.

So the total surface area is 428+216=644cm^2.

6 0
1 year ago
A term account earns 3.6%, compounded daily for 3 years. If the amount is $8411.02 at the end of the 3 year period, what was the
ValentinkaMS [17]

Answer:

7550

Step-by-step explanation:

AV=PV(1+\frac{i}{n} )^{nt}\\8411.02=PV(1+\frac{.036}{365})^{365*3}\\8411.02= PV*1.114\\PV= 7550

5 0
3 years ago
The answer to this problem?
LenaWriter [7]

The simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

<h3>How to simplify the expression?</h3>

The expression is given as:

\sqrt{\frac{162x^9}{2x^{27}}}

Divide 162 and 2 by 2

\sqrt{\frac{81x^9}{x^{27}}}

Take the square root of 81

9\sqrt{\frac{x^9}{x^{27}}}

Apply the quotient rule of indices

9\sqrt{\frac{1}{x^{27-9}}}

Evaluate the difference

9\sqrt{\frac{1}{x^{18}}}

Take the square root of x^18

\frac{9}{x^9}

Hence, the simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

Read more about expressions at:

brainly.com/question/723406

#SPJ1

5 0
1 year ago
In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad
weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

\angle acd = 60 ^{\circ}

Therefore, we have

\angle dcb =90- 60= 30 ^{\circ}

Now, in triangle bcd, we have

\tan30 = \frac{5}{cd}\\&#10;\\&#10;\frac{1}{\sqrt 3}=\frac{5}{cd}\\&#10;\\&#10;cd=5\sqrt 3

Now, in triangle acb, we have

tan 60 = \frac{ad}{5\sqrt3} \\&#10;\\&#10;\sqrt 3=  \frac{ad}{5\sqrt3}\\&#10;\\&#10;ad= 5\sqrt3 \times \sqrt 3\\&#10;\\&#10;ad= 5\times 3\\&#10;\\&#10;ad=15

Thus, ad is 15 cm.


4 0
3 years ago
A water sprinkler sprays in a circular pattern a distance of 10 ft from the sprinkler to the edge. What is the circumference of
vfiekz [6]

Answer:

<h2>62.8 ft</h2>

Step-by-step explanation:

7 0
3 years ago
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