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3 years ago

Which organelle should be listed under both animal cell and plant cell

Biology

2 answers:

ElenaW [278]3 years ago

8 0

Mitochondria is in both a plant cell and animal cell

Angelina_Jolie [31]3 years ago

8 0

Cell membrane, cytoplasm, nucleus, mitochondria, ribosomes, endoplasmic reticulum, vacuoles, golgi apparatus (;;;

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Euglena are not the only organisms that have flagellum. Zooflagellates are protozoan that also have flagella. Although euglena a

Assoli18 [71]

Possession of flagellum is not a taxonomic feature. many different unrelated organisms have flagellum. euglena, zooflagellates but also some fungi or even human sperm cells.

7 0

3 years ago

1. What term defines the ratio of the amount of water vapor actually in the air to the amount of water vapor that the air can ho

artcher [175]

Answer:

Relative humidity, RH

Explanation:

RH, is the ratio of the amount of water vapor present in the air to the maximum amount of water vapor needed for saturation at a certain pressure and temperature

4 0

3 years ago

small group of 100 people decide to isolate themselves from the world and move to a small and remote deserted island. Out of thi

irina [24]

Answer:

Frequency of p $= 0.684$

Frequency of p $= 0.316$

Number of individuals with homozygous dominant (AA) $= 47$

Number of individuals with heterozygous (Aa) $= 43$

Number of individuals with homozygous recessive (aa) $= 10$

Explanation:

Out of 100 people, 10 have albino skin (aa)

So, the frequency of homozygous recessive individuals $(q^{2})$ is $\frac{10}{100} = 0.1$

Now, q will be

$= \sqrt{q^{2} } = \sqrt{0.1} \\= 0.316$

As per Hardy Weinberg's equation -

$p + q = 1$

Substituting the value of q in above equation, we get -

$p + 0.316 = 1p = 1 -0.316\\p = 0.684$

Now the frequency of homozygous dominant (AA) will be

$p^{2} = 0.684^{2} \\= 0.467$

Hence, out of 100 people $0.467 * 100 = 46.7 or 47$ people are homozygous dominant (AA)

Like wise out of 100 people $0.1 * 100 = 10$ people are homozygous recessive (aa)

As per As per Hardy Weinberg's equation-

$p^{2} + q^{2} + 2pq = 1\\$

Substituting the values in above equation, we get -

$0.467 + 0.316 + 2pq = 1\\2pq = 1 -( 0.467+ 0.1)\\2pq = 0.433$

So, out of 100 people $0.433 * 100 = 43.3 or 43$ people are heterozygous (Aa)

7 0

4 years ago

Can anyone please answer this ?

iris [78.8K]

Answer:

It should be B.

Explanation:

7 0

3 years ago

Read 2 more answers

Is cytokinesis a part of mitosis ?

stich3 [128]

Cytokinesis is part of M-phase, but not part of Mitosis. M-phase consists of nuclear division (mitosis) and cytoplasmic division (cytokinesis). And yes, telophase is part of mitosis, so it's in M-phase <span>too.

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5 0

3 years ago