Question

int temp; temp = 180; if ( temp > 90 ) { System.out.println( "This porridge is too hot." ); // cool down temp = temp – ( temp > 150 ? 100 : 20 ); } // end if else { if ( temp < 70 ) { System.out.println("This porridge is too cold."); // warm up temp = temp + (temp < 50 ? 30 : 20); } // end if } // end else if ( temp == 80 ) System.out.println( "This porridge is just right!" );

Answer 1

Answer:

The combined output will be option D which is

This porridge is too hot.

This porridge is just right!

Explanation:

As the complete question is not the given the complete question is found online and is attached herewith.

Now from the given attached code

As the temperature value is 180 which is more than 90 so the first loop is true and the first print out is

This porridge is too hot.

Now the temperature is cooled down using the formula such that the temperature reduced 100 degrees in the intervals of 20 now the temperature becomes 80. As it is greater than 70, thus the second if loop is not executed.

As the temperature is 80 this the next print out will be as

This porridge is just right!

So the combined output will be option D which is

This porridge is too hot.

This porridge is just right!