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Vladimir [108]
3 years ago
10

Help with sectors of circles

Mathematics
1 answer:
Inessa05 [86]3 years ago
6 0

Answer:

Step-by-step explanation:

The perimeter is the arc length plus the two radius lines.

Arc length is:

s = (θ/360) 2πr

So the perimeter is:

P = (θ/360) 2πr + 2r

Given that θ=135 and r = 11:

P = (135/360) 2π(11) + 2(11)

P = 8.25π + 22

P ≈ 47.9

So the perimeter is greater than 47.5 cm.

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What is the solution of
Karolina [17]
Answer is b
there are 2 cases
1: if x is less than -5/3
then you have -3x-5=5x+2
solve and get x=-7/8 which is invalid

2: if x is more than -5/3
then you have 3x+5=5x+2
solve and get x=3/2 which is valid

so b is the answee
3 0
3 years ago
The distribution of the number of people in line at a grocery store has a mean of 3 and a variance of 9. A sample of the numbers
Airida [17]

Answer:

a) P(\bar X >4)=P(Z>\frac{4-3}{\frac{3}{\sqrt{50}}}=2.357)

P(Z>2.357)=1-P(Z

b) P(\bar X \frac{2.5-3}{\frac{3}{\sqrt{50}}}=-1.179)

P(Z

c)  

P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}

P(-1.179Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the number of people of a population, and for this case we know that:

Where \mu=3 and \sigma=\sqrt{9}=3

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(\bar X >4)= P(z> \frac{4-3}{\frac{3}{\sqrt{50}}})

And using a calculator, excel or the normal standard table we have that:

P(Z>2.357)=1-P(Z

Part b

P(\bar X  \frac{2.5-3}{\frac{3}{\sqrt{50}}})

And using a calculator, excel or the normal standard table we have that:

P(Z

Part c

For this case we want this probability:

P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}

And using a calculator, excel or the normal standard table we have that:

P(-1.179

7 0
3 years ago
Seventy-five percent of what number is 37.5?
Svetach [21]

Answer:  37.5 is 5% of 57.6923077

Step-by-step explanation:

4 0
4 years ago
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guapka [62]
Which one the highlight one
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kodGreya [7K]

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Unit 37-A do you copy?

Roger that Lieutenant.

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Let's move move move!!!

Alright kid, we got you covered. Come with us and you'll be fine

The end

8 0
3 years ago
Read 2 more answers
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