If this were to be graphed, the independent variable would be the price of the ticket for the rides. The dependent variable would be the total cost.
The fair admission is not a variable because it is a constant price for every single person who goes into the fair.
The problem asks to use y to represent the total cost and x to represent the number of ride tickets. In order to fully write out the equation, we have to figure out what the fair admission costs.
43.75 = 1.25(25) + b
*b represents the fair admission
Multiply 1.25 by 25
43.75 = 31.25 + b
Subtract 31.25 to find what b costs.
12.50 = b
The fair admission costs $12.50.
Solution: y = 1.25x + 12.50
3(x)-5=x+5
3x=-5+5+x
3x=x
0=x
because 3x=x is basically would make each part into 0 which would end up the same.
4.5 • 10-5 = 40
2.4 • 10-2 = 22
Answer:
50 over 1 (4n - 1) = 5050
I hope I helped you^_^
Answer:
The sweat chloride reference value is less than 30 mmol/L. A value of more than 60 mmol/L of chloride in the sweat is consistent with a diagnosis of cystic fibrosis. The values of 30-60 mEq/L may represent heterozygous carriers, these carriers cannot be accurately identified with a sweat chloride test.
