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Murljashka [212]
3 years ago
9

Solve the system y=x²-2 and x²+y=4.Illustrate graphically.

Mathematics
1 answer:
lawyer [7]3 years ago
4 0

Answer:

Solution: (-\sqrt{3},1),(\sqrt{3},1)

Step-by-step explanation:

System of equation:

y=x^2-2\text{ and }x^2+y=4

Using substitution method.

y=x^2-2 substitute into x^2+y=4

x^2+x^2-2=4              (combine like term)

2x^2=4+2                   (Addition property of equality)

2x^2=6                       (division property of equality)

x^2=3                          (Taking square root)

x=\pm \sqrt{3}

Substitute x into  y=x^2-2

y=(\sqrt{3})^2-2

y=1

Solution: (-\sqrt{3},1),(\sqrt{3},1)

Now cross check the solution using graph.

Please find attachment for graph.

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