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Lapatulllka [165]
3 years ago
14

Write as an algebraic expression and then simplify if possible The distance traveled by a train in three hours with a constant s

peed of r miles per hour.
Mathematics
1 answer:
Natalka [10]3 years ago
8 0

<u>Answer:</u>

Distance = 3r

<u>Step-by-step explanation:</u>

We are to write an algebraic expression and then simplify it for the given situation:

<em>The distance traveled by a train in three hours with a constant speed of r miles per hour.</em>

We know the formula of distance linking the speed and the time.

Distance = speed × time

Substituting the given values to get:

Distance = r × 3

Distance = 3r

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lapo4ka [179]
If k=20 minutes
Each day Sasha will exercise 2 times more. 2 times more than k is 2k.
So first week Sasha will exercise k+2k+3k+4k+5k+6k=20+40+60+80+100+120=440 minutes
The formula to show how long Sasha will exercise each day next week is:
440 + 20*x
where 440 is initial exercise time, and x is number of day in next week.
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4 years ago
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2 years ago
What's the pattern?<br> 1,2,4,8,16.....
Inessa05 [86]
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3 years ago
A gym charges a $25 sign-up fee plus $25 per month. You have a $200 gift card for the gym. When does the total spent on your gym
cestrela7 [59]

Answer:

After 7 months

Step-by-step explanation:

<u>DATA:</u>

<em>⇒ Sign-up fee = $25</em>

<em>⇒ Monthly fee = $25</em>

<em>⇒ Number of months = y</em>

<em>⇒ Gift card = $200</em>

<u><em>Form an equation to calculate when the total spent on gym would exceed the amount of the gift card</em></u>

Sign-up fee + (monthly fee x number of months) = Gift card amount

25 + 25y = 200

25y = 200-25

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y = 7

Therefore, the total spent on your gym membership exceeds the amount of your gift card after 7 months.

8 0
3 years ago
Using the Descartes Rule of Signs, describe the real zeroes of the function.
mrs_skeptik [129]

as you already know, Descartes rule of signs check the times the sign changes or f(x) and for f(-x)


\bf \stackrel{\textit{positive roots}}{f(x)=}\underset{change}{2x^5-}x^4\underset{change}{-2x^3+}4x^2\underset{change}{+x-2} \\\\\\ \stackrel{\textit{negative roots}}{f(~-x~)=}-2x^5\underset{change}{-x^4+}2x^3\underset{change}{+4x^2-}x-2


by the fundamental theorem of algebra, the polynomial has a degree of 5, so it has to have at most 5 zeros/solutions/roots.

f(x) has 3 sign changes, notice, that means, it has either 3, or (3-2), 1 positive zeros.

for f(-x), recall that x³, will be (-x)³ = (-x)(-x)(-x) = -x³, so in short, if the exponent is ODD, the sign changes for that term, if it's EVEN, it doesn't change.

so for f(-x), we have 2 sign changes, meaning, it has either 2 or (2-2), 0 negative roots.

the slack is picked up by the complex roots.

so

3 positive, 2 negative, 0 complex

or

1 positive, 2 negative, 2 complex  *recall complex always come in pairs*

or

3 positive, 0 negative, 2 complex

or

1 positive, 0 negative, 4 complex.

5 0
3 years ago
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