Answer:
= 70.2 ± 3.761 bpm
Step-by-step explanation:
The question is on calculating the confidence interval for a population mean
The general expression is
CI = x ± z * δ/√n where;
CI = confidence interval,
x = mean of sample,
δ = standard deviation,
n= is sample size
z = z* value from standard normal distribution according to confidence level given.
Given that;
n= 30 x =70.2 δ=10.51 z* for 95% CI = 1.96
Then applying the expression
CI = x ± z * δ/√n
![=\sqrt{n} = \sqrt{30} =5.477\\\\=\frac{10.51}{5.477} =1.919*1.96=3.761\\\\](https://tex.z-dn.net/?f=%3D%5Csqrt%7Bn%7D%20%3D%20%5Csqrt%7B30%7D%20%3D5.477%5C%5C%5C%5C%3D%5Cfrac%7B10.51%7D%7B5.477%7D%20%3D1.919%2A1.96%3D3.761%5C%5C%5C%5C)
Cl = 70.2±3.761
<u>= 70.2 ± 3.761 bpm</u>