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shusha [124]
3 years ago
7

How do you factor 5y2 - 12x - 9

Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0
5y² - 12x - 9

It can't be factored.
You might be interested in
Sarah ran 2 miles and Jaime ran 15, 840 feet. How many miles did they run together? (The conversion factor is 5280 feet/mile.)
Korvikt [17]

Answer:

C. 5 miles

Step-by-step explanation:

Since we need to find how many miles they ran together, let us convert feet to miles. Sarah's length is already in miles so we'll leave it that way.

Jaime ran 15840 feet. We are given how many feet are there in one mile (5280), so we need to find how many miles are there in 15840 feet.

x = 15840 / 5280 = 3 miles.

So, Jaime ran 3 miles and Sarah ran 2 miles.

That means that together they ran 3 + 2 = 5 miles.

6 0
3 years ago
How many feet of monkey grass would you need to go around a circular flower bed if you know that the area is 36π ft2?
Anvisha [2.4K]
12<span>π ft would be the answer

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8 0
2 years ago
Read 2 more answers
Michael borrows money from his uncle, who is charging him simple interest using the formula I = PRT. To figure out what the inte
katen-ka-za [31]

Answer:

c

Step-by-step explanation:

formula l=PRT

bring PT to right side we get

l/PT = R

or

R=l/PT

4 0
3 years ago
The​ ____ is another term for the arithmetic average.
antiseptic1488 [7]

The answer is the mean.

"For a data set, the arithmetic mean, also called the mathematical expectation or average, is the central value of a discrete set of numbers: specifically, the sum of the values divided by the number of values."- Wikipedia

3 0
3 years ago
The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and
kykrilka [37]

Answer:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

<u>15                       7.50                                 7.50  </u>

<u>∑                                                               17.0281</u>

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

8 0
3 years ago
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