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shusha [124]
4 years ago
7

How do you factor 5y2 - 12x - 9

Mathematics
1 answer:
Mamont248 [21]4 years ago
4 0
5y² - 12x - 9

It can't be factored.
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Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 5x minus 8 when x is less than 0 a
vlabodo [156]
The limit does not exist. Why? Because the left hand limit DOES NOT equal the right hand limit. Let’s double check:

We could use -0.000001 to represent the left hand limit. This is less than 0. We plug in 5x - 8

5(-0.000001) - 8
-0.000005 - 8
-8.000005
If we would continue the limit (extend the zeros to infinity), we would get exactly
-8
That is our left hand limit.

Our right hand limit will be represented by 0.000001. This is greater than 0. We plug in abs(-4 - x)

abs(-4 - (0.000001))
abs(-4.000001)
4.000001
If we would continue the limit (extend the zeros to infinity), we would get exactly
4

4 does not equal -8, therefore

The limit does not exist
4 0
3 years ago
Multiple Choice [x] + 5 = 18 A 5 or -5 B. 13 or -13 ​
Charra [1.4K]

Answer: don't know sorry

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Adam exchanged British pounds for Swiss franc He changed £400 into 592 francs What was the exchange rate of British pounds to Sw
OLEGan [10]

Answer: 1 : 1.48

Step-by-step explanation:

Adam was able to change £400 into 592 francs which means that the British pound is stronger because it was able to buy more Swiss francs.

The exchange rate can be gotten using direct proportion:

400 : 592

1       : x

Cross multiply:

400x = 592

x = 592/400

x = 1.48

Exchange rate is:

= 1 : 1.48

5 0
3 years ago
The fastest a human has ever run is 27 miles per hour. how many miles per minute did the human run?
vfiekz [6]
5 hours hope it help you
3 0
3 years ago
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The table shows values of a function. What is the average rate of change of over the interval from x = 5 to x = 9? Show your wor
Allushta [10]

\frac{f(9) - f(5)}{9 - 5}  \\  =  \frac{14 - ( - 2)}{4}  \\  =  \frac{16}{4}  \\  = 4

Hope this helps. - M
3 0
3 years ago
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