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viktelen [127]
3 years ago
9

Complete the graph for me plz I don’t know it I’m really confused and I have a C+ in math

Mathematics
1 answer:
Anna71 [15]3 years ago
8 0
Well, if the sulfur atoms is equal to 6 and the oxygen atoms is equal to twelve, then we are just multiplying by two so:

9 x 2= 18 so plug that in next
21 x 2=42
On the last one, you will want to divide by two to get the top

54/2=27

Hope I helped!
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Answer:

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Give the domain, range, intercepts, asymptotes, intervals of increasing and decreasing, intervals of positive and negative, symm
klemol [59]
y = \frac{3}{x^{2} - 4} + 1

Domain: x² - 4 ≠ 0
                 + 4 + 4
                    x² ≠ 4
                 √x² ≠ √4
                    x ≠ ±2
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Range: y ≠ 1
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Intervals: Increasing: (0.25 , ∞)
              Decreasing: (-∞, 0.25)

Symmetry: X-axis: Not Symmetric
                  Y-axis: Not Symmetric
                  Origin: Not Symmteric

Extrema: Maximum Relative: x = 0
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3 0
3 years ago
I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT
makvit [3.9K]

Answer:

BC = 22

Step-by-step explanation:

<b = <c  given

we now know it is an isosceles triangle

therefore AC = AB

AC=AB

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subtract x from each side

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x-24 =-2

add 24 to each side

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side BC = x

BC = 22


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professor190 [17]
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Firdavs [7]

Answer:

Answer from the answer data to choose from

<h2>3(x² + 3x - 1)</h2>

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Step-by-step explanation:

3x^2+9x-3=(3)(x^2)+(3)(3x)-(3)(1)\\\\=(3)(x^2+3x-1)\\\\\text{For}\ x^2+3x-1\ \text{use the quadratic formula}\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x^2+3x-1\to a=1,\ b=3,\ c=-1\\\\x=\dfrac{-3\pm\sqrt{3^2-4(1)(-1)}}{2(1)}=\dfrac{-3\pm\sqrt{9+4}}{2}=\dfrac{-3\pm\sqrt{13}}{2}=-\dfrac{3\pm\sqrt{13}}{2}\\\\3x^2+9x-3=3\left(x+\dfrac{3-\sqrt{13}}{2}\right)\left(x+\dfrac{3+\sqrt{13}}{2}\right)

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