Question

Factor completely. 49t 6 - 4k 8

Answer 1

Answer: It will become,

$49t^6-4k^4=(7t^3-2k^4)(7t^3+2k^4)$

Step-by-step explanation:

Since we have given that

$49t^6-4k^8$

We need to factorise the above expression:

$49t^6-4k^8\\\\=(7^2(t^2)^3-2^2(k^2)^4\\\\=(7t^3)^2-(2k^4)^2$

So, we can apply the identity :

$a^2-b^2=(a+b)(a-b)$

Here,

$a=7t^3\\\\b=2k^4$

so, it will become,

$49t^6-4k^4=(7t^3-2k^4)(7t^3+2k^4)$

Answer 2

(7t³ - 2k4)(7t³ - 2k4) is the correct awnser