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sertanlavr [38]
3 years ago
5

What is the y intercept of the exponential function? f(x)= - 1/3 (3)^(x+3) -1

Mathematics
1 answer:
kobusy [5.1K]3 years ago
5 0

Answer:

y- intercept = - 10 or (0, - 10 )

Step-by-step explanation:

to find the y-intercept, that is where the graph crosses the y- axis let x = 0 in the equation

f(0) = - \frac{1}{3} (3)³ - 1

     = - \frac{1}{3} × 27 - 1 = - 9 - 1 = - 10


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alina1380 [7]
Or on algebraic expression y= 3/2x+ 17/2

7 0
3 years ago
PLEASE:
Tju [1.3M]

Answer:

63.59 in²

Step-by-step explanation:

The formula to find the area of a square: a², where a is the side.

The formula to find the area of a circle: πr², where r is the radius (diameter ÷ 2), and the pi is alterable (3.14 or 3.142 or 22/7).

1) Find the diameter of the circle. The side of a square is the diameter.

a²

a = √81

a = 9

2) Plug the values into the formula of the area of a circle. 9 ÷ 2 = 4.5 (radius).

= 3.14 x 4.5²

= 3.14 x 20.25

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3) Round off the result to the nearest hundredth.

= 63.59

3 0
2 years ago
4.3/2.5 = x/4 what is the proportion
Inga [223]
X/4 = 4.3/2.5
x/4 = 1.72
x = 1.72 x 4
x = 6.88
7 0
3 years ago
This is a 3 part 1 question each part on how to locate the plane and a small explanation report working out the recovery details
sesenic [268]

Third leg.

The crew flies at a speed of 560 mi/h in direction N-20°-E.

The wind has a speed of 35 mi/h and a direction S-10°-E.

We then can draw this as:

We have to add the two vectors to find the actual speed and direction.

We will start by adding the x-coordinate (W-E axis):

\begin{gathered} x=560\cdot\sin (20\degree)+35\cdot\sin (10\degree) \\ x\approx560\cdot0.342+35\cdot0.174 \\ x\approx191.53+6.08 \\ x\approx197.61 \end{gathered}

and the y-coordinate (S-N axis) is:

\begin{gathered} y=560\cdot\cos (20\degree)-35\cdot\cos (10\degree) \\ y\approx560\cdot0.940-35\cdot0.985 \\ y\approx526.23-34.47 \\ y\approx491.76 \end{gathered}

Then, the actual speed vector is v3=(197.61, 491.76).

The starting location for the third leg is R2=(216.66, 167.67) [taken from the previous answer].

Then, we have to calculate the displacement in 20 minutes using the actual speed vector.

We can calculate the movement in each of the axis. For the x-axis:

\begin{gathered} R_{3x}=R_{2x}+v_{3x}\cdot t \\ R_{3x}=216.66+197.61\cdot\frac{1}{3} \\ R_{3x}=216.66+65.87 \\ R_{3x}=282.53 \end{gathered}

NOTE: 20 minutes represents 1/3 of an hour.

We can do the same with the y-coordinate:

\begin{gathered} R_{3y}=R_{2y}+v_{3y}\cdot t \\ R_{3y}=167.67+491.76\cdot\frac{1}{3} \\ R_{3y}=167.67+163.92 \\ R_{3y}=331.59 \end{gathered}

The final position is R3 = (282.53, 331.59).

To find the distance from the origin and direction, we transform the cartesian coordinates of R3 into polar coordinates:

The distance can be calculated as if it was a right triangle:

\begin{gathered} d^2=x^2+y^2_{} \\ d^2=282.53^2+331.59^2 \\ d^2=79823.20+109951.93 \\ d^2=189775.13 \\ d=\sqrt[]{189775.13} \\ d\approx435.63 \end{gathered}

The angle, from E to N, can be calculated as:

\begin{gathered} \tan (\alpha)=\frac{y}{x} \\ \tan (\alpha)=\frac{331.59}{282.53} \\ \tan (\alpha)\approx1.1736 \\ \alpha=\arctan (1.1736) \\ \alpha=49.56\degree \end{gathered}

If we want to express it from N to E, we substract the angle from 90°:

\beta=90\degree-\alpha=90-49.56=40.44\degree

Answer: the final location can be represented with the vector (282.53, 331.59).

1) The distance from the origin is 435.63 miles and

2) the direction is N-40°-E.

7 0
1 year ago
HELP PLEASE ITS DUE IN 10 MIN Use algebraic strategies to solve for x.
mr Goodwill [35]

Answer:

x = 4, x ≠ -1

Step-by-step explanation:

√3x + 4 = x

(√3x + 4)² = x² (Square both sides to get rid of the radical.)

3x + 4 = x²

0 = x² - 3x - 4 (Set everything to 0 by moving everything to one side.)

0 = (x - 4)(x + 1) (Factor.)

x = 4   x = -1

Now we need to check for extraneous solutions:

√3(4) + 4 = 4

√12 + 4 = 4

√16 = 4

4 = 4

√3(-1) + 4 = -1

√-3 +4 = -1

√1 = -1

1 ≠ -1

-1 is an extraneous solution.

8 0
3 years ago
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