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Arturiano [62]
3 years ago
9

Answers for 1,2,3 please. Thank you

Mathematics
1 answer:
lesantik [10]3 years ago
7 0
1. <em>B.) 6^{4}

</em>
2. <em>C.) 3 x 3 x 3 x 3 x 3</em><em />
<em>
</em>
<em />3. 
<em>a.) -5^{3}

b.) 1.05^{6}</em>


c.) <em>(-\frac{3}{5} )^{3}
</em>
<em />
<em />Here's a little explanation as to how we got those answers. A power is an exponent given to a number indicating that the base number is being multiplied by itself that many times. Here's an example:
<em>
</em>
4^{3}
<em />The 4 is our base number and it is given the exponent 3, so we would read this expression like so, " Four to the third power". That third power means that 4 is being multiplied by itself 3 times. so, it would look something like this:
<em>
4 x 4 x 4
16 x 4
64

</em>
4^{3} = 64
<em>
</em>Thank you for the question! I hope this helped! Have an amazing day! :D
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Determine, using the intermediate value theorem, if the function F(x)=x^3+2x-1 has a zero on the interval [0,1]. Justify your an
SSSSS [86.1K]

Plug x = 0 into the function

f(x) = x^3 + 2x - 1

f(0) = 0^3 + 2(0) - 1

f(0) = -1

Note how the result is negative. The actual number itself doesn't matter. All we care about is the sign of the result.

Repeat for x = 1

f(x) = x^3 + 2x - 1

f(1) = 1^3 + 2(1) - 1

f(1) = 2

This result is positive.

---------------------------

We found that f(0) = -1 and f(1) = 2. The first output -1 is negative while the second output 2 is positive. Going from negative to positive means that, at some point, we will hit y = 0. We might have multiple instances of this happening, or just one. We don't know for sure. The only thing we do know is that there is at least one root in this interval.

To actually find this root, you'll need to use a graphing calculator because the root is some complicated decimal value. Using a graphing calculator, you should find the root to be approximately 0.4533976515

7 0
3 years ago
You found the prime factorization of the number 73 explain how you can check your answer
antoniya [11.8K]

9514 1404 393

Explanation:

You can check your answer by making sure that each of the primes you found is actually a prime. (Compare to a list of known primes, for example.) After you have determined your factors are primes, multiply them together to see if the result is 73. If so, you have found the correct prime factorization.

__

<em>Additional comment</em>

73 is prime, so its prime factor is 73.

  73 = 73

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3 years ago
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Hmm it would be k(x)=2(5x) or it could be k(x)=10x

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Step-by-step explanation:

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