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3 years ago

14

I need the answerssssssssssssssssssssssss

1 answer:

swat323 years ago

8 0

A) 9cm
B) 0.54m
C) idk I’d it’s right but it’s 137.7
Hope this helps

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1.6 × 10^6 ÷ 4.8 × 10^5. Give your answer as a mixed number

Tasya [4]

Answer:

(10^11)/3

10^6 x 10^5 = 10^11

8/5 x 5/24 = 1/3

so multiply 10^11 and 1/3 together

6 0

2 years ago

15 POINTS ANSWER ASAP, SHOW WORK

forsale [732]

Answer:

$V=97.6\ in^3$

Step-by-step explanation:

step 1

Find the volume of the cylinder

The volume of the cylinder is equal to

$V=\pi r^{2}h$

we have

$r=4/2=2\ in$ ---> the radius is half the diameter

$h=8\ in$

substitute

$V=\pi (2)^{2}(8)\\\\V=32\pi\ in^3$

step 2

Find the volume of the cone

The volume of the cone is equal to

$V=\frac{1}{3}\pi r^{2} h$

we have

we have

$r=2\ in$ ---> the radius is the same that the radius of the cylinder

$h=0.70\ in$

substitute

$V=\frac{1}{3}\pi (2)^{2} (0.70)\\\\V=0.93\pi\ in^3$

step 3

Find the volume of the plastic object

we know that

The volume of the plastic object is equal to the volume of the cylinder minus the volume of the cone

so

$V=32\pi-0.93\pi=31.07\pi\ in^3$

assume

$\pi=3.1416$

$V=31.07(3.1416)=97.6\ in^3$

8 0

2 years ago

How many integers have absolute value equal to five? what are the integers justify the answer

velikii [3]

Answer:

5,-5

Step-by-step explanation:

|x|=a

x=±a

|x|=5

x=±5

3 0

3 years ago

raketka [301]

Answer:

its b

Step-by-step explanation:

4 0

3 years ago

Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam

Vlad [161]

Answer

$P(A) = 0.30$

$P(B) = 0.77$

$P(A\ n\ B) = 0.22$

$P(A\ u\ B) = 0.85$

Explanation:

Given

See attachment for proper data presentation

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

Here:

$Yes = 22$ and $No = 8$

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

$P(A) = 0.30$

Solving (b): P(B)

We only consider data in the Yes column.

Here:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

$P(B) = 0.77$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

i.e. [Supplier 1][Yes]

This is represented as: n(A n B)

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ n\ B) = 0.22$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

$P(A\ u\ B) = 0.85$

7 0

2 years ago