Let ABC the vertices of the EQUILATERAL triangle inscribed in the circle centered in O & with R as radius (sketch it to better understand)
Join OA & OB so that to calculate the area of sector BOA
Mesure Angle C = 1/2 mes Arc AB, but C =60° , then Arc AB = 120°
So the central angle AOB = mes ARC OAB = 120°
The area of a sector = mes angle BOA x R² (mind you angle should be in radian) Angle BOA = 120°or 2π/3 (in radian) the Area Sect = (2π/3).R²
Answer:
- 439
Step-by-step explanation:
evaluate f(- 7) and substitute the value obtained into s(x)
f(- 7) = 3(- 7) = - 21 , then
s(- 21) = 2 - (- 21)² = 2 - 441 = - 439
Answer:
No. 1 , 3 and 5 is correct.
Answer:
c
Step-by-step explanation:
