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3 years ago

Find the range from 4 to -2 A. 2 B. 4 C. 6 D.-2

Mathematics

2 answers:

Scilla [17]3 years ago

7 0

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ The range is the highest value minus the smallest value

Therefore, you just need to subtract the two values to find the values:

-2 - 4 = -6

The difference is just 6, so your answer is C. 6

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

Alla [95]3 years ago

3 0

C. 6 because you find the range by subtracting the lowest number from the highest number in a set of data and 4 is your highest number and -2 is the lowest number and your supposed to do 4 - -2 which equals 6

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Write the equation of the line in fully simplified slope-intercept form.

PtichkaEL [24]

Answer:

Consider points (0, -5) and (-6, -1)

» General equation of a line:

${ \tt{y = mx + c}}$

m is slope
c is y-intercept

 Slope (m):

${ \tt{m = \frac{ - 1 - ( - 5)}{ - 6 - 0} }} \\ \\ { \tt{m = \frac{4}{ - 6} }} \\ \\ { \tt{m = - \frac{2}{3} }}$

 y-intercept (c):

${ \tt{y = mx + c}}$

consider point (0, -5)

${ \tt{ - 5 = c}} \\ { \tt{c = - 5}}$

Equation:

${ \boxed{ \tt{y = - \frac{2}{3} x - 5}}}$

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2 years ago

Una ciudad tenía 8000 habitantes a final del año 2000. Cada año su población se incrementa en un 0.5 %

Digiron [165]

Answer:

The correct answer is 2030.

Step-by-step explanation:

To start we must analyze the information we have.

We know that a city has 8000 inhabitants and that each year this number increases by 0.5%. That means that each year it has 40 more inhabitants:

(8000 . 0,5) : 100 = 40

Having this information we could do a cross multiplication:

1 year ------- 40 inhabitants

x years ------- 81200

81200 = 40.x

x = 81200 : 40

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In this way we can verify that the correct answer is 2030.

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3 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

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3 years ago

Amy had homework for math,science,and history.she spent 1/3 of her time working on math and 1/4 of her time working on science.

Alja [10]

First we need to multiply to make the fractions have equal denominators so we can add/subtract.

math: 1/3 x 4/4=4/12
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Now we can find the time she spent on history (I assume this is what you are looking for)

Total time-math time-science time=history time
12/12-4/12-3/12
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Amy spent 5/12 of her time working on history.

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2 years ago

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Marta_Voda [28]

Answer:

Step-by-step explanation:

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