Question

A trianglar carpet is laid in a square room of side 12m, if the base of the carpet is 10m and the height is 8m, calculate the area of the floor uncoverd​

Answer 1

Answer :

◈ Area of square room :

$:\implies\sf\:A_s=(side)^2$

$:\implies\sf\:A_s=(12)^2$

$:\implies\bf\:A_s=144\:m^2$

◈ Area of triangular carpet :

$:\implies\sf\:A_t=\dfrac{1}{2}\times base\times perpendicular$

$:\implies\sf\:A_t=\dfrac{1}{2}\times 10\times 8$

$\:\implies\sf\:A_t=\dfrac{1}{2}\times 80$

$:\implies\bf\:A_t=40\:m^2$

◈ Uncovered area of room :

$:\implies\sf\:\Delta A=A_s-A_t$

$:\implies\sf\:\Delta A=144-40$

$:\implies\:\boxed{\bf{\blue{\Delta A=104\:m^2}}}$