We can proceed in solving the problem since all information are given such as 2*4*5costheta.
we have a=4, b=5, and C=theta
let us solve for "c" using Pythagorean
c²=a²+b²
c²=4²+5²
c=6.4
Solving for theta or C
c²=a²+b²-2abcosC
6.4²=4²+5²-2*4*5*cosC
C=90
Answer:
incomplete
Step-by-step explanation:
please send the full information, I can't see students belonging to acers
Given the question:
The manager of a baseball team has 15 players to choose from for his
9-person batting order. How many different ways can he arrange the
players in the lineup?
5,005
362,880
3,603,600
1,816,214,400
The number of was in which a smaller group is choosing from a bigger group is given by the bigger number combination the smaller number.

Here, we want to choose a 9-person batting order from a team of 15 players. This is given by:
G=5(z+s)
70=5(z+6)
70=5z+30
40=5z
z=8
Zane is 8
First you have to divide the 9 on both sides to get x alone. Next you would have to divide 117 and 9. (117÷9=13) . So x>13