Step-by-step explanation:
4(a-3b) - 2(a-2b)
4a - 12b - 2a - 4b
2a - 16b
The correct answer is C).
The easiest way to answer this is to try all choices, plug
in values for the 1st term and 2nd term then check if the
answer matches with 5 and 2. (n = 1 and n = 2)
We know that n starts with 1 because that is our 1st
term, we do not have 0th term, therefore that leaves us with 2
choices.
Choice 1: an = 5 − 2(n − 1); all integers where n ≥ 1
n = 1
a1 = 5 – 2 (1 – 1) = 5 – 2 (0)
a1 = 5
n = 2
a2 = 5 – 2 (2 – 1) = 5 – 2 (1)
<span>a2 = 3 (FALSE!)</span>
Choice 2: an = 5 − 3(n − 1); all integers where n ≥ 1
n = 1
a1 = 5 – 3 (1 – 1) = 5 – 3 (0)
a1 = 5
n = 2
a2 = 5 – 3 (2 – 1) = 5 – 3 (1)
<span>a2 = 2 (TRUE)</span>
Therefore the correct answer is:
<span>an = 5 − 3(n − 1); all integers where n ≥ 1</span>
Answer:
Step 3: Choice D
Step 5: Choice B
Step 6: Choice A
Step 8: Choice C
(I saw in the top left corner of the picture that this is for Algebra II. I am in 8th grade, currently taking geometry, and I haven't taken Algebra II yet, but I <em>did</em> take Algebra I last year. I am 95% sure this is correct but if it isn't, the I sincerely apologize.)
