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maria [59]
2 years ago
7

What is the classification for this polynomial?

Mathematics
1 answer:
Mariana [72]2 years ago
4 0

Answer:

Trinomial

Step-by-step explanation:

This is because there are three terms involved in the equation.

One of them is -7ab^4. Another is 4c^3. The third one is 25.

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The measure of an angle is 133°. What is the measure of its supplementary angle?
Pachacha [2.7K]

Answer:

47

Step-by-step explanation:

180 - 133 = 47

7 0
2 years ago
What are the values of m and n
Natasha2012 [34]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The required values are ~

  • m = 60 \degree

  • n = 30 \degree

Refer to attachment for solution ~

7 0
2 years ago
Which of the following ordered pairs could represent the x-intercept of a function?
bearhunter [10]
The answer is (15,0) because the format is (x,y) so (15,0) means that it is on the x axis only ! 
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3 years ago
PLEASE HELP !! ILL GIVE BRAINLIEST !!
viktelen [127]

Answer:

<em>Angle </em><em>VUX </em><em>and </em><em>angle</em><em> </em><em>WXU </em><em> </em>

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8 0
2 years ago
Read 2 more answers
Alexander Litvinenko was poisoned with 10 micrograms of the radioactive substance Polonium-210. Since radioactive decay follows
koban [17]

Answer:

The amount of Polonium-210 left in his body after 72 days is 6.937 μg.

Step-by-step explanation:

The decay rate of Polonium-210 is the following:

N(t) = N_{0}e^{-\lambda t}     (1)

Where:

N(t) is the quantity of Po-210 at time t =?

N₀ is the initial quantity of Po-210 = 10 μg

λ is the decay constant  

t is the time = 72 d  

The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.    

First, we need to find the decay constant:

\lambda = \frac{ln(2)}{t_{1/2}}    (2)

Where t(1/2) is the half-life of Po-210 = 138.376 days

By entering equation (2) into (1) we have:

N(t) = N_{0}e^{-\frac{ln(2)}{t_{1/2}}*t}} = 10* \frac{99.498}{100}*e^{-\frac{ln(2)}{138.376}*72} = 6.937 \mu g    

Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.  

I hope it helps you!  

8 0
2 years ago
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