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Salsk061 [2.6K]
3 years ago
5

 What is the radius of a cone with diameter​ d? An ice cream cone is filled exactly level with the top of the cone. The cone has

a 5​-cm diameter and 9​-cm depth. Approximate how much ice cream​ (in cm cubed​) is in the​ cone? Use 3.14 for pi. What is the radius of a cone with diameter​ d?
Mathematics
1 answer:
alekssr [168]3 years ago
5 0

Answer:

radius is 2.5

volume of ice cream is 58.9 cm cubed

Step-by-step explanation:

to calculate the volume of a cone   v=pi x r^2 x (h/3)

v=volume

r=radius

h=height

^ means powers and roots

depth in cones is the same as height

v=3.14 x 2.5^2 x (9/3)

order of operations

v=3.14 x 2.5^2 x 3

v=3.14 x 6.25 x 3

v=19.625 x 3

v=58.875

round

v=58.9

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MIDPOINT & DISTANCE help
tamaranim1 [39]

Answer:

<h2>M(-6, 4)</h2>

Step-by-step explanation:

The formula of a midpoint of (x₁, y₁) and (x₂, y₂):

M\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

We have two points (-3, 7) and (-9, 1).

Substitute:

x=\dfrac{-3+(-9)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{7+1}{2}=\dfrac{8}{2}=4

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3 years ago
What is the value of the discriminant? 4x2+15x=3x-9
Ray Of Light [21]

Answer:

0

Step-by-step explanation:

Use the values of  a ,  b , and  c  to find the discriminant.

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2 years ago
At a fair, each person can spin two wheels of chance. The first wheel has the letters F, A, I, and R. The second wheel has the n
pickupchik [31]

Answer:

12 possible outcomes.

Sample space:

\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}

Step-by-step explanation:

The collection of all possible outcomes of a probability experiment forms a set that is known as the sample space.

1. There are four possible outcomes for the first wheel: F, A, I and R

2. There are three possible outcomes for the second wheel: 1, 2 and 3

So, the sample space is

\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}

4 0
2 years ago
What is the median of the data set?<br><br><br><br> 9<br> 8.5<br> 8<br> 10
Allushta [10]

Answer:

8.5

Step-by-step explanation:

When you write out the data set, it looks like this:

5, 8, 8, 8, 8, 9, 9, 9, 10, 10

The median means the exact middle of the data set. In this case, it falls between the 8 and the 9, so the middle would be 8.5, so that's the median of the set. I hope this helps :)

6 0
2 years ago
Read 2 more answers
A ski lift is designed with a total load limit of 20,000 pounds. It claims a capacity of 100 persons. An expert in ski lifts thi
Yanka [14]

Answer:

0.5 = 50% probability that a random sample of 100 independent persons will cause an overload

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sum of n values of a distribution, the mean is \mu \times n and the standard deviation is \sigma\sqrt{n}

An expert in ski lifts thinks that the weights of individuals using the lift have expected weight of 200 pounds and standard deviation of 30 pounds. 100 individuals.

This means that \mu = 200*100 = 20000, \sigma = 30\sqrt{100} = 300

If the expert is right, what is the probability that a random sample of 100 independent persons will cause an overload

Total load of more than 20,000 pounds, which is 1 subtracted by the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 20000}{300}

Z = 0

Z = 0 has a pvalue of 0.5

1 - 0.5 = 0.5

0.5 = 50% probability that a random sample of 100 independent persons will cause an overload

5 0
3 years ago
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