Answer:
Step-by-step explanation:
Let's write a system.
Let's say that the variables are x and y.
xy=48
x+y=14
Solve for one of the variables, let's say, x.
x=14-y.
Now substitute x into the 1st equation.
(14-y)y=48
Simplify.
-y²+14y=48
Make it into a quadratic equation.
-y²+14y-48=0
Make sure y²'s coefficient is one. Divide everything by -1
y²-14y+48=0
Now factor!
What factors add up to 14 and multiply to 48.
6 and 8!
Since the 2nd term is negative, and the 3rd term is positive, the factors have to be negative.
y²-6y-8y+48=0
Group.
(y²-6y)+(-8y+48)=0
y(y-6)-8(y-6)=0
(y-8)(y-6)=0
y-8=0
y-6=0
y=8 y=6
now let's substitute each y value into y²-14y+48=0
8²-14(8)+48=0
64-112+48=0
0=0. so y=8 checks out!
6²-14(6)+48=0
36-84+48=0
0=0 so y=6 also checks out!
Choose one y value and solve for x, in each equation :
xy=48
x+y=14
8x=48
x+8=14
x=6
x=6
It checks out!
so the factors are
x=6 y=8.
