In 'n' 10! ways, books can be arranged. But, there are also 5! permutation of blue books 'n1', 2! permutation of identical green books 'n2', and 3! permutation identical black books 'n3'.

Therefore, for non identical arrangements:

$\frac{n!}{n1!n2!n3!}$

$\frac{10!}{5!2!3!}$ = 2520

Therefore, the books can be arranged on a shelf in 2520 patterns

8 0

3 years ago

Please help me, if you help then thanks!

lara31 [8.8K]

Answer:

x = 5

Step-by-step explanation:

${x}^{3} = 125$

${x}^{3} = {5}^{3}$

$x = 5$

8 0

3 years ago

What is the product in lowest terms? 8/15 * -3/10

german

Multiply the numerators and denominators together:

-24/150

Divide the numerator and denominator by 6:

-24 / 6 = -4
150 / 6 = 25

-4/25

4 0

3 years ago

What digits can be in the ones place of a number that has 5 as a factor?

Sophie [7]

The digits that can be in the ones place is 1 and 5.... I think.

3 0

3 years ago