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Nesterboy [21]
3 years ago
15

Please help with this

Mathematics
1 answer:
Arturiano [62]3 years ago
7 0

The missing side of the triangles are 5, 16.92, 7 and 5 respectively.

Step-by-step explanation:

  • Step 1: Use the Pythagoras Theorem to find the missing sides.

a² + b² = c²

In the first triangle, a = 3, b = 4.

c² = 3² + 4² = 9 + 16 = 25

⇒ c = 5

∴ Missing side is 5

In the second triangle, a = 15, b = 8

c² = 15² + 8² = 225 + 64 = 289

⇒ c = 16.92

Missing side is 16.92

In the third triangle, b = 24, c = 25

a² = c² - b²

a² = 25² - 24² = 625 - 576 = 49

⇒ a = 7

Missing side is 7

In the fourth triangle, a = 12, c = 13

b² = c² - a²

b² = 13² - 12² = 169 - 144 = 25

⇒ b = 5

Missing side is 5

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m∠AOB = 6x + 5, m∠BOC = 4x - 2, m∠AOC = 8x + 21
AnnZ [28]
The sum of angle AOB and angle BOC is equal tot he angle of AOC so

6x+5 +4x-2 = 8x+21

10x+3=8x+21

Subtract three and 8x from both sides

2x=18

Divide by two

x=9

Hope this helped!
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