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Nesterboy [21]
3 years ago
15

Please help with this

Mathematics
1 answer:
Arturiano [62]3 years ago
7 0

The missing side of the triangles are 5, 16.92, 7 and 5 respectively.

Step-by-step explanation:

  • Step 1: Use the Pythagoras Theorem to find the missing sides.

a² + b² = c²

In the first triangle, a = 3, b = 4.

c² = 3² + 4² = 9 + 16 = 25

⇒ c = 5

∴ Missing side is 5

In the second triangle, a = 15, b = 8

c² = 15² + 8² = 225 + 64 = 289

⇒ c = 16.92

Missing side is 16.92

In the third triangle, b = 24, c = 25

a² = c² - b²

a² = 25² - 24² = 625 - 576 = 49

⇒ a = 7

Missing side is 7

In the fourth triangle, a = 12, c = 13

b² = c² - a²

b² = 13² - 12² = 169 - 144 = 25

⇒ b = 5

Missing side is 5

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All the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over. After 60 additional boxe
AveGali [126]

Answer:

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

Step-by-step explanation:

Given that all the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over.

This implies that boxes are in multiples of 12

i.e. 12, or 24, or 36 or....

Let us say this as 12m for m an integer

Now additional boxes arrived =60

Total number of boxes now = 12m+60

This when arranged in stacks of 14,nothing left out

Or this is multiple of 14

12m+60 = 14n for some positive integer n.

By trial and error we find that if 60 is to be divided by 14, 24 should be added and 24 is a multiple of 12.

So we say originally 24 boxes were there now 84 boxes there.

Hence both options are right.

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

3 0
3 years ago
Use the given graph to determine the limit, if it exists. (4 points)
skelet666 [1.2K]
<h3>Answer:  3</h3>

Explanation:

Refer to the graph below. It should be similar to what your teacher gave you, based off the description.

Since we're approaching 3 from the right side, this means we'll be working with the horizontal line portion. We could start at something like x = 3.2 and move closer to 3 by getting to x = 3.1 then x = 3.01 then x = 3.001 and so on. We never actually get to 3 itself.

As x gets closer to 3 from this direction, the y values are approaching 3 since every point on this horizontal line has the same y coordinate. Technically the y value is already at 3, but it's the same idea.

In terms of notation, we can write \displaystyle \lim_{x\to3^{+}}f(x) = 3

The portion x \to 3^{+} means we're approaching 3 from the positive side, aka the right hand side on the number line.

8 0
2 years ago
Find the sum.
Strike441 [17]

You are gonna use the distributive property.

4(2.5g - 4) + 3(1.2g - 2)

So you are going to multiply 4 with everything inside the first set of parenthesis and your gonna multiply 3 with everything insides the second set of parenthesis.

4 x 2.5g - 4 x 4 + 3 x 1.2g - 3 x 2

10g - 16 + 3.6g - 6

You wanna combine like terms:

10 - 3.6g + 16 - 6

6.4g + 10

You answer is 6.4g + 10.

Hope this Helps!!

6 0
3 years ago
Find the area of the shape below.
m_a_m_a [10]

Answer:

 A_{shape}=A_{triangle}+A_{square}\\\\A_{shape}=(\frac{bh}{2}+s^2)\ units^2

Step-by-step explanation:

I assume that it is a composed figure formed by a triangle and a square.Since you did not  give the dimensions of the triangle and the dimensions of the square, I will giveyou  a general explanation about how to solve this exercise.

The area of the shape will be the sum of the the area of the square and the area of the triangle.

Then, you need to remember that the area of a triangle can be calculated with the following formula:

A_{triangle}=\frac{bh}{2}

Where "b" is the base and "h" is the height.

And the area of a square can be found with this formula:

A_{square}=s^2

Where "s" is the length of any side of the square.

Therefore, the area of the shape will be

 A_{shape}=A_{triangle}+A_{square}\\\\A_{shape}=(\frac{bh}{2}+s^2)\ units^2

3 0
3 years ago
Y’all. I need you to help me
Sergio039 [100]

Answer:

10

Step-by-step explanation:

PQ/QR = ST/TR

17.5/QR = 7/4

QR = (17.5 x 4)/7

QR = 70/7

QR = 10

3 0
3 years ago
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