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USPshnik [31]
3 years ago
13

(y+2x+3)dx+(x- 4y^3 +2)dy 0

Mathematics
1 answer:
denis-greek [22]3 years ago
3 0

Answer:

=dx(y+2x+3)

I hope that helps you

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Solve If QR = 6x + 1, PR = 14x - 13, and PQ = 5x - 2, find PR
solong [7]

Answer:

P____Q____R

PR= PQ+ QR

(14x-13) = (5x-2)+(6x+1)

14x-13= 11x – 1

14x – 11x = 13–1

3x = 12

x= 12/ 3

x= 4

PR= 14x – 13 = 14 (4) – 13 = 18 – 13= 5

If you want (PQ , QR ) this is the solution

PQ =5x-2=5(4)-2=20-2=18

QR =6x+1=6(4)+1=24+1=25

I hope I helped you^_^

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3 years ago
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Order these numbers from least to greatest.<br> 5.7082, 5.09, 5.009, 5.7
matrenka [14]

Answer:

5.7082,5.009,5.09,5.7

Step-by-step explanation:

5 0
3 years ago
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How do you simplify -3x²ym + 7x - 5ymx² + 16x
brilliants [131]
 you cant add or subtract or multiply or divide if the variables arent the same so the simplified version of <span>-3x²ym + 7x - 5ymx² + 16x would be 
</span> -3x²ym <span>- 5ymx² + 23x</span>
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Factorise polynomial<br> 27y3 + 125z3<br><br>​
tresset_1 [31]

Answer:

27y^{3} +125z^{3} =(3y)^{3} +(5z)^{3}

Apply the formula for sum of cubes: a^{3}+b^{3}=(a+b)(a^{2}-ab+b^{2})

Therefore:

\left(3y\right)^3+\left(5z\right)^3=\left(3y+5z\right)\left(3^2y^2-3\cdot \:5yz+5^2z^2\right)

=\left(3y+5z\right)\left(9y^2-15yz+25z^2\right)

6 0
3 years ago
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