Answer:I need help with that too :(
Step-by-step explanation:
Answer:
La afirmación es falsa, no todos los divisores de 100 son divisores de 50, ya que solo se toman en cuenta sus divisores comunes, los cuales son todos los divisores de 50. Expresamos a 100 en sus factores primos: 100 = 2 · 2 · 5 · 5 = 2² · 5² Divisores de 100: {1, 2, 4, 5, 10, 20, 25, 50, 100}
Step-by-step explanation:
For this case we have the following expressions:
x-3
Y
Adding both expressions we have:
(x-3) + (y)
Rewriting we have:
x - 3 + y
y + x - 3
Answer:
The sum of the quantity x-3 and y is:
y + x - 3
B, c and d would be the answer
This is a Reflection :) Have a great day !
