2 years ago

Help I need the answer

1 answer:

4 0

A. -3+4i Square both numbers, add them, then find the square root. Essentially, use the Pythagorean theorem. -3^2 + 4^2 9 + 16=25 Square root of 25 is 5.

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For the function F(x) = 1/x+2, which of these could be a value of F(x) when xis

hram777 [196]

Answer:

B 2

Step-by-step explanation:

The computation of the value of f(x) in the case when x = 2 is shown below

As per the question, following function is given

F(x) = (1 ÷ x) + 2

Based on this, the x = 2

Now put the x value in the above equation

So,

= (1 ÷ 2) + 2

= (1 + 4) ÷ 2

= 5 ÷ 2

= 2.5

Hence the closet number is 2

Therefore the value of f(x) in the case when x = 2 is 2

Hence, the correct option is b.

5 0

2 years ago

Read 2 more answers

Y=(2x-3)^5(2-x^4)^3 differentiate the function please

BARSIC [14]

$\bf y=(2x-3)^5(2-x^4)^3\\\\
-------------------------------\\\\
\cfrac{dy}{dx}=\stackrel{\textit{product rule}}{[5(2x-3)^4\cdot 2(2-x^4)3]~~+~~[(2x-3)^5[3(2-x^4)^2(-4x^3)]]}
\\\\\\
\cfrac{dy}{dx}=10(2x-3)^4(2-x^4)^3~~-~~12x^3(2x-3)^5(2-x^4)^2
\\\\\\
\cfrac{dy}{dx}=\stackrel{\textit{common factor}}{2(2x-3)^4(2-x^4)^2}~[5(2-x^4)-6x^3(2x-3)]
\\\\\\
\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2~[10-5x^4-12x^4+18x^3]
\\\\\\
\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2(10-17x^4+18x^3)$