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lbvjy [14]
3 years ago
13

Help I need the answer

Mathematics
1 answer:
timurjin [86]3 years ago
4 0
A. -3+4i Square both numbers, add them, then find the square root. Essentially, use the Pythagorean theorem. -3^2 + 4^2 9 + 16=25 Square root of 25 is 5.
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8 customers entered a store over the course of 16 minutes. At what rate were the customers entering the store in minutes per cus
lilavasa [31]

Answer:

<h3>2min/customer</h3>

Step-by-step explanation:

If 8 customers entered a store over the course of 16 minutes, then;

8 customers = 16 minutes.

The rate at which the customers are entering is expressed as;

Rate = Time (in minutes)/amount of customers;

Given

Time = 16 minutes

Amount of customers = 8 customers

Rate = 16min/8customers

Rate = 2min/customer

Hence the rate at which the customers entering the store in minutes per customer is 2min/customer.

4 0
2 years ago
How many solutions can be found for the equation 4z 2(z − 4) = 3z 11? none one two infinitely many
Rus_ich [418]

There is only one solution for the equation 4z + 2(z -4) = 3z + 11 because the exponent for the power of z is 1.

<h3>What is an equation?</h3>

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

<h3>What is the Solution?</h3>

A solution is any value of a variable that makes the specified equation true.

According to the given information:

4z + 2(z-4)= 3z+11

Solve the equation,

4z+2z-8=3z+11

6z-3z=11+8

3z =19

z=

Hence,

Number of solution that can be found for the equation 4z + 2(z-4)= 3z+11 is option(2) one

To know more about Equations and Solutions visit:

brainly.com/question/545403

#SPJ4

8 0
2 years ago
Two corresponding sides of similar triangles are 2 cm and 5 cm. What is the area of the second triangle if the area of the first
Stella [2.4K]

Answer:

(1) Area of second triangle= 50 cm^2.

(2) Area of ΔABC=98 cm^2.

   and Area of ΔDFG=175 cm^2.

Step-by-step explanation:

<em>" For two similar triangles the ratio of sides is equal to the ratio of square of their areas".</em>

i.e. if a,b are the corresponding sides of two similar triangles and let A and B denote the area of two triangles then we have the relation as:

\dfrac{a^2}{b^2}=\dfrac{A}{B}

(1)

for the first question:

we have a=2, b=5.

A=8 cm^2.

Hence,

\dfrac{2^2}{5^2}=\dfrac{8}{B}\\\\\dfrac{4}{25}=\dfrac{8}{B}

B=50 cm^2.

Hence, the area of second triangle is 50 cm^2.

(2)

In second option we have:

a=6 and b=5.

A-B=77 cm^2.

A=77+B

\dfrac{6^2}{5^2}=\dfrac{A}{B}\\  \\\dfrac{36}{25}=\dfrac{77+B}{B}\\  \\36B=25\times77+25B\\\\36B-25B=25\times77\\\\11B=25\times77\\\\B=25\times7\\\\B=175

Hence area of second triangle i.e. ΔDFG is 175 cm^2.

and area of first triangle i.e. ΔABC=175-77=98 cm^2.




8 0
2 years ago
A rectangle has the following vertices. Find the area of the rectangle. (9, −1), (−1, 7), (−5, 2), (5, −6)
stiks02 [169]

Answer:  82 sq. units .

Step-by-step explanation:

Let A (9, −1), B (−1, 7), C(−5, 2), D(5, −6) are the vertices of rectangle.

Then we plot them on graph ( as provided in attachment)

Length = AB =\sqrt{(9+1)^2+(-1-7)^2} units  [By distance formula : \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]

=\sqrt{(10)^2+(-8)^2}=\sqrt{100+64}=\sqrt{164}=2\sqrt{41} units

Width = BC = \sqrt{(-1+5)^2+(7-2)^2} units

=\sqrt{4^2+5^2}\\\\=\sqrt{16+25}\\\\=\sqrt{41}

Area = length x width

= 2\sqrt{41}\times\sqrt{41}=2\times41= 82\text{ sq. units}

Hence, the  area of the rectangle is 82 sq. units .

7 0
3 years ago
Which is the degree measure of an angle whose tangent is 5.67?
kolbaska11 [484]

Answer:

80 degrees.

Step-by-step explanation:

7 0
2 years ago
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