REUPLOAD!! (Worth 10 Points Each I Believe.) (please zoom / zoom out if needed to see question. (: )

Mathematics

2 answers:

irakobra [83]3 years ago

5 0

I'm trying to help you in a easy way. Just multiply the numbers for part 1. And then add the numbers u multiplied from part 1 all together and you will have your answer for part 2. Lol don't report this because i am not good at multiplying so ye but this is what i would have done.

Dmitry [639]3 years ago

4 0

Step 1:
Wall 1: 9 * 18 = 162 sq ft
Wall 2: (21*9) - (7*6) = 147 sq ft
Wall 3: (18*9) - (7*4) = 134 sq ft
Wall 4: (21*9) - (4*3) = 177 ft (I'm assuming you want to subtract the thing in the middle that looks like a window for wall 4)

Step 2:
Add up all the areas of the 4 walls : 162+147+134+177= 620 sq ft

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Which of the following equations can represent the function graphed below? Select all the possible

11Alexandr11 [23.1K]

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Step-by-step explanation:

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2 years ago

The graph shows the result of a matrix transformation, where the pre-image has dashed lines Which matrix operation is represente

diamong [38]

The matrix operation is the addition subtraction and multiplication involving matrices. The coordinates of the image can be represented as a matrix obtained from the coordinates of the preimage through matrix operations

The best correct option is option D), (the y-coordinate for the point (8, -7) is to be replaced with a 7 to give (7, -7) as follows:

$\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]$

The reason the above matrix value for the matrix operation are correct are as follows:

Known parameters:

From the diagram, we have that the coordinates of the vertices of the preimage are;

(2, -5), (3, -7), (9, -3), and (7, -7)

The coordinates of the vertices of the image are;

(2, 5), (3, 7), (9, 3), and (7, 7)

Required:

The matrix operation for the transformation of the preimage points to the image points

Solution:

The transformation from the coordinates of the vertices of primage to the vertices of image involves the change in the sign from negative to positive, of the y-values of the image, which can be obtained by multiplying by (-1)

Therefore, the required matrix operation is presented as follows:

$\mathbf{\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]} =\left[\begin{array}{rrrr}9&7&3&2\\3&7&7&5\end{array}\right]$