How to draw a line that passrs through the origion and has a slope of 2/3?

1 answer:

6 0

The origin is (0,0)

y = mx + b
slope(m) = 2/3
(0,0)...x = 0 and y = 0
now we sub and find b, the y int
0 = 2/3(0) + b
0 = b

so ur equation is y = 2/3x + 0...or just y = 2/3x

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