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kogti [31]
3 years ago
10

What happens as the cross section moves away from the side to which it is parallel?

Mathematics
2 answers:
boyakko [2]3 years ago
7 0

Answer:

he cross section becomes smaller but stays a trapezoid.

Step-by-step explanation:

BaLLatris [955]3 years ago
7 0

Answer:

The cross section becomes smaller but stays a trapezoid.

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A pair of vertical angles have the measure of 2y + 5 degrees + 4y degrees what is the value of y​
timama [110]

Answer:

The value of y s 2.5

Step-by-step explanation:

Vertical angles are always equal to one another. In this case, we can find the angles by setting the two values equal and solving algebraically.

2y + 5 = 4y

5 = 2y

2.5 = y

7 0
3 years ago
What is the equation for this graph pls help me and pls make sure it’s right:))
SVETLANKA909090 [29]

Answer:

y = 5x + 4

Step-by-step explanation:

First I found the slope by using the the definition that slope is rise/run so I saw that the y value went up from 4 to 9 which is 5 units and then the x value went up one in that same time. This means that the slope is 5/1. Then I found the y intercept by seeing where x = 0. On the graph you can see the line touches the y - axis at a value of 4 which means that the y - intercept is 4. Plugging these values into the y = mx + b equation you get y = 5x + 4.

8 0
3 years ago
Read 2 more answers
A toy rocket is launched vertically from 5 feet above ground level with an initial velocity of 112 feet per second. The height h
Masja [62]

Answer:

Step-by-step explanation:

a)The height h after t seconds is given by the equation h(t)=-16t^2+112t+5.

Where 5 represents 5feet above the ground and this is the height from which the rocket was launched.

The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height travelled by the rocket.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = -16

b = 112

Vertex = - - 112/32= 3.5

So the rocket will attain maximum height at 3.5 seconds.

It will also take 3.5 seconds to reach the ground. This means it will take a total of 3.5 seconds + 3.5 seconds

= 7 seconds to hit the ground.

b) to find time it will take to be 100 feet above the ground,

-16t^2+112t-95 = 0

Using general quadratic equation formula,

a = -16

b = 112

c = -95

t = [-b+/-√b^2-4ac]/2a

t = [ -112 +/-√112^2-4×-16×-95]/16 × -2

= [-112 +/-√12544-6080]/-32

= (-112+80.4)/-32 or (-112-80.4)/-32

t = 0.9875 or t = 6.0125

So it will take 0.9875 or approximately 1 second to be 100 feet above the ground

7 0
3 years ago
Evan is going to the country fair this weekend. The admission to the fair is $10
ankoles [38]
I need more information.
6 0
3 years ago
Solve this please <br> 6x = 1,620
mylen [45]
6 x 270= 1,620
I hope this helped
8 0
4 years ago
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