Factor completely 2x^3+6x^2+2x+6

2 answers:

6 0

F(-3) = 2*-27 + 6*9 + 2*-3 + 6 = 0

so x + 3 is a factor

dividing the function by x + 3 gives the quotient

2x^2 + 2 = 2 (x^2 + 1)

So the factors are 2(x^2 + 1)(x + 3) Answer

posledela3 years ago

4 0

<span>2x^3+6x^2+2x+6
= 2(</span><span>x^3 + 3x^2 + x + 3)
= 2[x^2 (x + 3) + (x + 3)]
= 2(x^2 + 1)(x + 3)

hope it helps</span>

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