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Vitek1552 [10]
3 years ago
8

Emily sold 96 boxes of cookies for a fundraiser. If she sold 60% of the total boxes of cookies sold for the fundraiser, how many

boxes of cookies were sold for the fundraiser total?
Mathematics
1 answer:
iragen [17]3 years ago
5 0
Emily sold 96 boxes ....this is 60% of the total boxes...

60% of the total boxes sold = 96
0.60x = 96....with x being the total boxes sold
x = 96 / 0.60
x = 160 <== there were a total of 160 boxes
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\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

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\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

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Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

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Now to C!

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\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

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So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

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