Answer: There is 125 mL of a 2.0 M CuCl2 solution are needed to make 500 mL of a 0.5 M solution
Explanation:
Given: = 2.0 M, = ?
= 0.5 M, = 500 mL
Formula used to calculate the volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that there is 125 mL of a 2.0 M solution are needed to make 500 mL of a 0.5 M solution.
Answe 174.0 KPA
Explanation:
0°C in 101.3 K PA pressure a sample of gas occupies 30 mL if the temperature is increased to 30°C in the entire gas sample is transferred to a 20 mL container what will be the gas pressure inside a container
PV=nRTt
so
n = PV/RT
P = 101.3 KPA
T = 0+273.2 = 273.200
V = (30/1000) L = 0.03 L
R =0.082
SO
n= (101.3 X 0.03)/(0.082 X 273.2)
= 0.14 moles
PV= nRT
N= 0,14
T = 30 + 273.2= 303.2
V= (20/1000)L =0.02L
since PV = nRT
THEN
P=nRT/V
so
P=(0.14 X 0.082 X 303.2)/0.02 =
174.0 KPA
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Answer:
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