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DiKsa [7]
3 years ago
8

There are 14 books on a shelf. .5 of them are new. The rest of them are used. What is the ratio of all books on the shelf to use

d books?
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0

Answer:

9/14

Step-by-step explanation:

You might be interested in
Solve this equation using order and operations:
exis [7]

Answer:

(1680)

Step-by-step explanation:

Simplify the following:

3 (10 (6 + 2 (22 + 8) - 10))

| 1 |  

| 2 | 2

+ | | 8

| 3 | 0:

3 (10 (6 + 2×30 - 10))

2×30 = 60:

3 (10 (6 + 60 - 10))

6 + 60 = 66:

3 (10 66 - 10)

| 6 | 6

- | 1 | 0

| 5 | 6:

3 (10×56)

10×56 = 560:

3 (560)

3 (560) = (3×560):

(3×560)

3×560 = 1680:

Answer: (1680)

5 0
3 years ago
The quotient of 8 and twice a number z
juin [17]
2z divided by 8
Z= 16
4 0
3 years ago
A large fish tank at an aquarium needs to be emptied so that it can be cleaned. When its
VikaD [51]

Answer:

The draining time when only the big drain is opened is 2.303 hours.

The draining time when only the small drain is opened is 5.303 hours.

Step-by-step explanation:

From Physics, we know that volume flow rate (\dot V), measured in liters per hour, is directly proportional to draining time (t), measured in hours. That is:

\dot V \propto \frac{1}{t}

\dot V = \frac{k}{t} (Eq. 1)

Where k is the proportionality constant, measured in liters.

From statement, we have the following three expressions:

(i) <em>Large and small drains are opened</em>

\dot V_{s}+\dot V_{l} = \frac{k}{2} (Eq. 2)

\frac{\dot V_{s}+\dot V_{l}}{k} = \frac{1}{2}

(ii) <em>Only the small drain is opened</em>

\dot V_{s} = \frac{k}{t_{l}+3} (Eq. 3)

\frac{\dot V_{s}}{k} = \frac{1}{t_{l}+3}

(iii) <em>Only the big drain is opened</em>

\dot V_{l} = \frac{k}{t_{l}} (Eq. 4)

\frac{\dot V_{l}}{k}  = \frac{1}{t_{l}}

By applying (Eqs. 3, 4) in (Eq. 2) and making some algebraic handling, we find that:

\frac{1}{t_{l}+3}+\frac{1}{t_{l}} = \frac{1}{2}

\frac{t_{l}+t_{l}+3}{t_{l}\cdot (t_{l}+3)} = \frac{1}{2}

2\cdot t_{l}+3 = t_{l}^{2}+3\cdot t_{l}

t_{l}^{2}-t_{l}-3 = 0 (Eq. 5)

Whose roots are determined by the Quadratic Formula:

t_{l,1}\approx 2.303\,h and t_{l,2} \approx -1.302\,h

Only the first roots offers a solution that is physically reasonable. Hence, the draining time when only the big drain is opened is 2.303 hours. And the time needed for the small drain is calculated by the following formula:

t_{s} = 2.303\,h+3\,h

t_{s} = 5.303\,h

The draining time when only the small drain is opened is 5.303 hours.

7 0
3 years ago
Round off 0.065 to one significant figure
Dmitrij [34]
I think what you are wanting id 0.1 is that rounded to one significant figure

5 0
3 years ago
Read 2 more answers
The length of Albert's rectangular are listed below.
trapecia [35]
A. Length - 100 ft Width - 50 ft is the measurement of Tony's backyard.

Albert's Perimeter = 2(l+w) = 2(40+20) = 2(60) = 120 ft.

Tony's Perimeter = 120 ft * 2.5 = 300 ft
Tony's length = 40 ft * 2.5 = 100 ft
Tony's widht = 20 ft * 2.5 = 50 ft

To check tony's perimeter:
P = 2(l + w) = 2 (100 + 50) = 2 (150) = 300 ft. 
3 0
3 years ago
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