Question

Determine the axis of symmetry and the vertex of the given function.

Answer 1

The vertex is (3,3) and the axis is 3

Answer 2

Answer:

Vertex is (3,3)

Axis of symmetry is x=3

Step-by-step explanation:

Given : Function $y = 2x^2 -12x + 21$

To find : The axis of symmetry and the vertex of the given function.

Solution :

The given function is in the form of quadratic equation $y=ax^2+bx+c$

Comparing with the given function $y = 2x^2 -12x + 21$

a=2 , b=-12  and c=21

x-coordinate of axis of symmetry and vertex

Axis of symmetry is given by $x=-\frac{b}{2a}$

Substitute the value,

$x=-\frac{-12}{2(2)}$

$x=\frac{12}{4}$

$x=3$

For y-coordinate of axis substitute x=3 in y

$y = 2(3)^2 -12(3) + 21$

$y = 2(9)-36+ 21$

$y = 18-15$

$y = 3$

Therefore, The vertex of function is (3,3).