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Anastaziya [24]

3 years ago

12

$15 represents 20% of the spending money Arie is saving for camp this summer. What is the total amount of money she hopes to tak

e to camp?

1 answer:

S_A_V [24]3 years ago

4 0

20% of camp spending money = 15

0.20x = 15
x = 15 / 0.20
x = 75 <==

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The wildflowers at a national park have been decreasing in numbers. There were 1200 wildflowers in the first year that the park

bonufazy [111]

Year New flowers

1 1200

2 300

3 75

There were 1200 wildflowers in the first year that the park started tracking them. Since then, there have been one fourth as many new flowers each year

Initially there are 1200 flowers and start decreasing by $\frac{1}{4}$

So first term is 1200 and common ratio is $\frac{1}{4}$ .

Its a geometric sequence so summation becomes

i =1∑ ∞ 1200( $\frac{1}{4})^{i-1}$

Now we find the sum

We use sum formula

$Sum = \frac{a}{1-r}$

Where a is the first term , a= 1200

r is the common ratio , r= 1/4

$Sum = \frac{1200}{1-(\frac{1}{4})}$

$Sum = \frac{1200}{\frac{3}{4}}$

Sum = 1600 wildflowers

4 0

4 years ago

How many solutions does this equation have?<br><br> –4j = –8j + 4j

emmainna [20.7K]

Answer:

Your Mom just remember your a di*k and thats why your parents burned your birth certifcate

Step-by-step explanation:

if your gonna do that to me, remember i have copy and paste<3.

5 0

3 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

4 0

3 years ago

Please help me with this quadratic equation question! I always give out 5 stars, thanks and brainliest to people that help me wi

ss7ja [257]

Answer:

$p=25,\\q=12$

Step-by-step explanation:

In $(ax+b)(cx+d)=acx^2+bcx+dax+bd$ , notice the third term of the quadratic in standard form is formed entirely by $b\cdot d$ .

Therefore, in $12x^2 - 13x - 7175 = (x-p) (qx + 287)$ :

$-p\cdot287=-7175,\\-p=\frac{-7175}{287},\\p=\fbox{$25$}$ .

Now that we found $p$ , we must find $q$ . The first term of the quadratic in standard form is formed entirely by $ax\cdot cx$ . Therefore:

$1\cdot q=12, \\q=\fbox{$12$}$ .

3 0

3 years ago

How can you use a 10-by-10 grid to model 12%? You can shade half of the squares. You can shade half of one row of the squares. Y

TiliK225 [7]

Answer:

The options provided do not have the correct answer. Read below.

Step-by-step explanation:

Given a 10 by 10 grid model means that there are exactly 100 individual squares present. This shows that each square is equal to 1%.

None of the options provided gives us 12% of the model.

The first option results in 50%, the second results in 5%, third option results in 0.5% and the last option results in 2%.

For 12% we can shade 12 squares completely, half of 24 squares etc.

I hope this answer helps.

3 0

3 years ago