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3 years ago

Dan drove 9 miles south and 12 miles east. What is the shortest distance to his starting point?

1 answer:

3 0

Working out the hypotenuse
a^2+b^2=c^2
9^2+12^2=c^2
81+144=225

square root of 225 = 15
therefore 15 miles is the shortest distance

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An isosceles triangle’s altitude will bisect its base. Which expression could be used to find the area of the isosceles triangle

omeli [17]

Answer:

$\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}$

Step-by-step explanation:

The length of the base is the distance between the points 4+2i and 10+4i, so

$\text{Base}=|10+4i-(4+2i)|=|10+4i-4-2i|=|6+2i|=\sqrt{6^2+2^2}=\\ \\=\sqrt{36+4}=\sqrt{40}$

The middle point of the base is placed at point

$\dfrac{4+2i+10+4i}{2}=\dfrac{6i+14}{2}=7+3i$

The length of the height is the distance between the points 5+9i and 7+3i

$\text{Height}=|5+9i-(7+3i)|=|5+9i-7-3i|=|-2+6i|=\sqrt{(-2)^2+6^2}=\\ \\=\sqrt{4+36}=\sqrt{40}$

So, the area of the triangle is

$A=\dfrac{1}{2}\cdot \text{Base}\cdot \text{Height}=\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}$

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3 years ago

The circle C has centre A(2,1) and passes through the point B(10,7). Find and equation for C

Semmy [17]

The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the centre
r - the radius

$A(2,1) - \hbox{the centre} \\
h=2 \\ k=1 \\ \\
(x-2)^2+(y-1)^2=r^2 \\ \\
\hbox{passes through B(10,7)} \\
x=10 \\
y=7 \\ \\
(10-2)^2+(7-1)^2=r^2 \\
8^2+6^2=r^2 \\
64+36=r^2 \\
r^2=100 \\ \\
\hbox{the equation:} \\ \boxed{(x-2)^2+(y-1)^2=100}$

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Answer:

Step-by-step explanation:

it will be 3 if you want to find the positive number

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Answer:

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