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4 years ago

A pair of parallel lines is cut by a transversal what is the measure of angle x

Mathematics

2 answers:

laiz [17]4 years ago

7 0

Answer:

x=65°

Step-by-step explanation:

Here we are given a pair of parallel lines and a transversal line intersecting at two points.

We know that the alternate interior angles are equal to each other

please refer to the attached file. Here we see that D=J

and D=x+15

Hence x+15=80

subtracting 15 from both sides we get

x=80-15

x=65

Hence our answer is x=65°

serious [3.7K]4 years ago

3 0

X = 80 - 15
x = 65

answer
65 degrees

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70 - q -q - 2q = 80 <br> plz help me i don't get it

Montano1993 [528]

Answer:

the answer is: q = -2.5

Step-by-step explanation:

70 - q - q - 2q = 80

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3 years ago

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pickupchik [31]

X=0 because when you have something to the power of zero your answer is 1.
x=0 since 1 to the power of zero equals 1.

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3 years ago

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1. (a) Solve the differential equation (x + 1)Dy/dx= xy, = given that y = 2 when x = 0. (b) Find the area between the two curves

erastova [34]

(a) The differential equation is separable, so we separate the variables and integrate:

$(x+1)\dfrac{dy}{dx} = xy \implies \dfrac{dy}y = \dfrac x{x+1} \, dx = \left(1-\dfrac1{x+1}\right) \, dx$

$\displaystyle \frac{dy}y = \int \left(1-\frac1{x+1}\right) \, dx$

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When x = 0, we have y = 2, so we solve for the constant C :

$\ln|2| = 0 - \ln|0 + 1| + C \implies C = \ln(2)$

Then the particular solution to the DE is

$\ln|y| = x - \ln|x+1| + \ln(2)$

We can go on to solve explicitly for y in terms of x :

$e^{\ln|y|} = e^{x - \ln|x+1| + \ln(2)} \implies \boxed{y = \dfrac{2e^x}{x+1}}$

(b) The curves y = x² and y = 2x - x² intersect for

$x^2 = 2x - x^2 \implies 2x^2 - 2x = 2x (x - 1) = 0 \implies x = 0 \text{ or } x = 1$

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$\left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^2 \le y \le 2x - x^2\right\}$

The area of this region is

$\displaystyle \int_0^1 ((2x-x^2)-x^2) \, dx = 2 \int_0^1 (x-x^2) \, dx = 2 \left(\frac{x^2}2 - \frac{x^3}3\right)\bigg|_0^1 = 2\left(\frac12 - \frac13\right) = \boxed{\frac13}$

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3 years ago

Over which interval is the graph of f(x) = –x2 + 3x + 8 increasing?

vivado [14]

Hello there!

To find the increasing intervals for this graph just based on the equation, we should find the turning points first.

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Set f'(x) equal to 0...
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This means that the x-value of our turning point is 3/2. Now we need to analyze the equation to figure out the end behavior of this graph as x approaches infinity and negative infinity.
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This means that the interval by which this parabola is increasing is...
(-∞,3/2)

PLEASE DON'T include 3/2 on the increasing interval because it's a turning point. The slope of the tangent line to the turning point is 0 so the graph isn't increasing OR decreasing at this point.

I really hope this helps!
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