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lesya [120]
3 years ago
15

what are the coordinates of the point on the directed line segment (-1,-2) to (9,-10) that partitions the segment into a ratio o

f 3 to 1
Mathematics
1 answer:
Ymorist [56]3 years ago
4 0

Answer:

[6.5,-7.25]

Step-by-step explanation:

Given the partitioning ratio as 3:1

#Find the length of the x-coordinate and multiply by the ratio:

x length=9--1=10

=>\frac{1}{4}\times 10=2.5

#We subtract 2.5 from the x-max to get the point=9-2.5=6.5

#Find the length of the y-coordinate and multiply by the ratio:

x length=-9--2=-7

=>\frac{1}{4}\times -7=-1.75

#We subtract -1.75 from the y-max to get the point=-9--1.75=-7.25

Hence,  the coordinates that partitions the segment into a ratio of 3 to 1 is [6.5,-7.25]

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Alenkinab [10]
It can be written as √64·√x¹⁶ = 8x⁸, so answer B.
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3 years ago
What are the x and y intercepts for -2x+y=-2​
SpyIntel [72]

Answer: The y intercepts would be: ( 0 , -2 ).

The x intercepts would be: ( 1 , 0 ).

Step-by-step explanation:

8 0
2 years ago
2. Sam is climbing 2/3 meters every 1/3 of an hour. How many meters does
ICE Princess25 [194]

Answer:

2/9

Step-by-step explanation:

if u multiply 2/3 × 1/3 u get 2/9

4 0
3 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
Oksana_A [137]
<h2>Hello!</h2>

The answers are:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

7 0
3 years ago
Name the property the equation illustrates (ab)3=a(b3)
Anvisha [2.4K]
The answer to this rests on knowing that there are four properties of multiplication (which your teacher will likely expect you to know...):

These are:
1. commutative
2. associative
3. multiplicative identity
4. distributive

I won't define each of these -- they should be in your notes or textbook. Look them up.

In this case, we are multiplying three terms together -- on the left hand side the parentheses mean to multiply a and b first, then multiply that by 3. On the right hand side, we multiply b times 3 first, and then multiply the product by a.

This would be an example of the associative property of multiplication: when three or more factors are multiplied together, the product is the same regardless of how the factors are grouped.

Hope this helps!

Good luck
3 0
3 years ago
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