Answer:
Step-by-step explanation:
Garrett achieves a field goal is independent of each kick. Hence X no of kicks is binomial with p = 0.83, and q =0.17
No of trials 3
Hence X can take values as 0 ,1,2,3 and
![P(X=r) = 4Cr(0.83)^r (0.17)^{4-r}](https://tex.z-dn.net/?f=P%28X%3Dr%29%20%3D%204Cr%280.83%29%5Er%20%280.17%29%5E%7B4-r%7D)
, r=0,1,2,3
Using the above we obtain prob distribution as
X 0 1 2 3
P(X) 0.0049 0.0720 0.3513 0.5718
P(X>=2) =P(X=2,3,4) =0.9231
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2) Z value for company A =![\frac{260-272}{5.4} =-2.22](https://tex.z-dn.net/?f=%5Cfrac%7B260-272%7D%7B5.4%7D%20%3D-2.22)
Z value for company B = ![(260-249)/3.8 =2.89](https://tex.z-dn.net/?f=%28260-249%29%2F3.8%20%3D2.89)
From z value probablility is more for company A as
P(Z>-2.22) >P(Z>2.89)
Answer: 0.3
Step-by-step explanation:
Answer: OPTION A.
Step-by-step explanation:
By definition, a dilation can be an enlargement or a reduction of the shape.
An enlargement is when dilation creates a larger image and a reduction is when dilation creates a smaller image.
When, the scale factor is greater than 1, the image is an enlargement and when the scale factor is between 0 and 1, the image is a reduction.
It is important to know that with a negative scale factor the enlargement will will be inverted and it will also be on the other side of the center of dilation.
Knowing this, we can say that the scale factor that will result in an enlargement is:
![k](https://tex.z-dn.net/?f=k%3C-1)
Answer:
The answer to your question is He must get 80%
Step-by-step explanation:
Data
Scores 55%, 78%, 84%, 93% and X
Average 80%
Process
1.- Write a equation to solve this problem
- There are five scores
Score 1 = S1 = 55
Score 2 = S2 = 78
Score 3 = S3 = 84
Score 4 = S4 = 93
Score 5 = S5 = X
Equation
Average = (S1 + S2 + S3 + S4 + S5) / 5
- Solve for S5
5 Average = S1 + S2 + S3 + S4 + S5
S5 = 5 Average - S1 - S2 - S3 - S4
- Substitution
S5 = 5(80) - 55 - 78 - 84 - 93
- Simplification
S5 = 400 - 310
- Result
S5 = 90
Answer:
![area = 200.96 \: {units}^{2} \\ circumfrence = 50.24 \: units](https://tex.z-dn.net/?f=area%20%3D%20200.96%20%20%5C%3A%20%7Bunits%7D%5E%7B2%7D%20%20%5C%5C%20circumfrence%20%3D%2050.24%20%5C%3A%20units)
Step-by-step explanation:
The formula to find the area and circumference of a circle is:
![area = \pi {r}^{2} \\ circumfrence = 2\pi \: r](https://tex.z-dn.net/?f=area%20%3D%20%5Cpi%20%7Br%7D%5E%7B2%7D%20%20%5C%5C%20circumfrence%20%3D%202%5Cpi%20%5C%3A%20r)
<em>*</em><em>no</em><em>te that pi is 3.14*</em><em> </em>Therefore the area is:
![formula = \pi {r}^{2} \\ 3.14 \times {8}^{2} = \\ 3.14 \times 64 = 200.96](https://tex.z-dn.net/?f=formula%20%3D%20%5Cpi%20%7Br%7D%5E%7B2%7D%20%20%5C%5C%203.14%20%5Ctimes%20%20%7B8%7D%5E%7B2%7D%20%20%3D%20%20%5C%5C%203.14%20%5Ctimes%2064%20%3D%20200.96)
Therefore the circumference is:
![formula = \: 2\pi \: r \\ (2)(3.14)(8) = \\ 3.14 \times 16 = 50.24](https://tex.z-dn.net/?f=%20formula%20%3D%20%5C%3A%202%5Cpi%20%5C%3A%20r%20%5C%5C%20%282%29%283.14%29%288%29%20%3D%20%20%5C%5C%203.14%20%5Ctimes%2016%20%3D%2050.24)