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frozen [14]
3 years ago
5

PLEASE HELP ME!!

Mathematics
1 answer:
liraira [26]3 years ago
3 0
Part A: 3m+15+27m

(sorry man, I cant really help you with b :/)
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A vertex of square is at(1,1) and its two parallel sides are y=x and y=x+1. find the equation of the remaining sides.Show your w
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Answer:

\displaystyle y  =   - x  +  2

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Step-by-step explanation:

we are given a vertex of a square i.e <u>(</u><u>1</u><u>,</u><u>1</u><u>)</u>

and the equations of the two parallel sides

notice that, the given vertex coordinates satisfy one of the parallel side i.e <u>y=</u><u>x </u>which means that (1,1) points lie on one of Parallel sides

remember that,

every angles of a square is <u>9</u><u>0</u><u>°</u><u> </u>

therefore,

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\displaystyle  m_{  \rm perpedicular} =  - 1

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\displaystyle y - 1 =  - 1(x - 1)

distribute:

\displaystyle y - 1 =  - x  +  1

add 1 to both sides:

\displaystyle y  =   - x  +  2

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so the slope of the perpendicular line is -1

and the equation:

y - 0.5 =  - 1(x - 0.5)

distribute:

y - 0.5 =  - x  +0 .5

add 0.5 to both sides:

y =  - x  +1

and we are done!

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