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pshichka [43]
3 years ago
12

Ella is stuffing envelopes. She has 48 red pages, 25 white pages, and 84 blue pages. If she need to put 2 red pages, 1 white pag

es, and 4 blue pages in every envelope to make it complete, how many complete envelopes can she make?
Mathematics
1 answer:
Marina CMI [18]3 years ago
4 0

Divide each number of pages she has, with the number of pages required.

48 red pages divided by 2 red pages.

48 ÷ 2 = 24

25 white pages divided by 1 white pages.

25 ÷ 1 = 25

84 blue pages divided by 4 blue pages.

84 ÷ 4 = 21

Now add the total amount.

24 + 25 + 21 = 70

Ella can make 70 envelopes.

☺

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Answer:

B

Step-by-step explanation:

When finding the area of a circle you have to use the formula

Area= Pie x radius^2

Radius=8.5

So you have to plug that into the equation.

8.5x8.5=72.25

72.25x3.14=226.87

So Area is 226.87

So your answer is B

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Naddika [18.5K]
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3 years ago
Need answer please and this a part 1 to this math hw spam
vlada-n [284]

Answer: -2.85

Step-by-step explanation:

To convert 22/20 into a decimal, we must multiply it by 5 to get a denominator of 100.

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So now lets solve the equation.

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PLEASE HELP. WILL GIVE BRAINLIEST
KengaRu [80]

Answer:

x-intercepts = 1,2, and 4, y-intercept = -8

Step-by-step explanation:

x^3 - 7x^2 - 14x - 8 in factored form is equal to (x-1)(x-2)(x-4).

Solving for x-intercepts:

  • We are actually able to solve for all x-intercepts without the given factor. But since we are given one of the factors, our job becomes much easier.
  • Using synthetic division, or long division, we factor out the x-intercept 4. Which leaves us with the polynomial x^2 - 3x + 2.
  • From here we can separate the polynomial into two binomials.
  • x^2 - 3x + 2 = (x-1)(x-2). Giving us all 3 x-intercepts.
  • Using Descartes' rules we can identify before even starting the problem how many real x-intercepts there are (Not needed for this problem).

Solving for y-intercept:

  • The y-intercept is always the coefficient that does not have any assigned x-variables.
  • The coefficient is -8, thus the y-intercept.
  • If unsure of the y-intercept, you can always plug in x = 0. Solving for the y-intercept will give you the value of f(0).
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4 0
3 years ago
I was never good with fractions, could someone help?
tangare [24]

Answer:

Thus, the answer is:

\left \{ {{x=4} \atop {y=2}} \  \atop {z=-4}} \right

Step-by-step explanation:

Considering the system of equations

\left \{ {{x+y+z=2} \atop {4x+y+z=14}} \  \atop {x-y+4z=-14}} \right\}

Rewrite the system in matrix form and solve it by Gaussian Elimination (Gauss-Jordan elimination)

\left \{ {{x+y+z=2} \atop {4x+y+z=14}} \  \atop {x-y+4z=-14}} \right\}\rightarrow \left[\begin{array}{ccc}1&1&1:2\\4&1&1:14\\1&-1&4:-14\end{array}\right]

R2 - 4 R1 → R2 (multiply 1 row by 4 and subtract it from 2 row); R3 - 1 R1 → R3 (multiply 1 row by 1 and subtract it from 3 row)

  \left[\begin{array}{ccc}1&1&1:2\\0&-3&-3:6\\0&-2&3:-16\end{array}\right]

R2 / -3 → R2 (divide the 2 row by -3)

\left[\begin{array}{ccc}1&1&1:2\\0&1&1:-2\\0&-2&3:-16\end{array}\right]

R1 - 1 R2 → R1 (multiply 2 row by 1 and subtract it from 1 row); R3 + 2 R2 → R3 (multiply 2 row by 2 and add it to 3 row)

\left[\begin{array}{ccc}1&0&0:4\\0&1&1:-2\\0&0&5:-20\end{array}\right]

R3 / 5 → R3 (divide the 3 row by 5)

\left[\begin{array}{ccc}1&0&0:4\\0&1&1:-2\\0&0&1:-4\end{array}\right]

R2 - 1 R3 → R2 (multiply 3 row by 1 and subtract it from 2 row)

\left[\begin{array}{ccc}1&0&0:4\\0&1&0:2\\0&0&1:-4\end{array}\right]

Thus, the answer is:

\left \{ {{x=4} \atop {y=2}} \  \atop {z=-4}} \right

Make a check:

4 + 2 + (-4) = 4 + 2 - 4 = 2

4·4 + 2 + (-4) = 16 + 2 - 4 = 14

4 - 2 + 4·(-4) = 4 - 2 - 16 = -14

Check completed successfully.

7 0
3 years ago
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